無法檢索數據庫中的輸出數據

Question

我正在使用以下PHP代碼從數據庫檢索商店信息字段，但在運行PHP時遇到下面顯示的錯誤。

<?php 
include ('database.php'); 


$locLat ; 
$locLng ; 
$shopName; 
$shopContact; 

$sql = "SELECT s_iD, s_name,s_contNo,s_lat,s_long from tbl_shop"; 

$result = mysqli_query($con,$sql); 
$arrayResult = array(); 

while ($row = mysqli_fetch_array($result)){ 
    array_push($arrayResult,array("id"=>$row['s_iD'],"shopName"=>$row['s_name'],"shopContact"=>$row['s_contNo'],"latitude"=>$row['s_lat'], 
     "longitude"=>$row['s_long'])); 
} 

echo json_encode (array('result'=> $result)); 


mysqli_close($con); 

但是輸出總是：

{ 「結果」：{ 「current_field」：NULL， 「場計數」：NULL， 「長度」：NULL， 「NUM_ROWS」：NULL，」類型「：空}}

Answer 1

這裏是你更新的代碼應該是：

<?php 
include ('database.php'); 


$locLat ; 
$locLng ; 
$shopName; 
$shopContact; 

$sql = "SELECT s_iD, s_name,s_contNo,s_lat,s_long from tbl_shop"; 

$result = mysqli_query($con,$sql); 
$arrayResult = array(); 

while ($row = mysqli_fetch_array($result)){ 
    array_push($arrayResult,array("id"=>$row['s_iD'],"shopName"=>$row['s_name'],"shopContact"=>$row['s_contNo'],"latitude"=>$row['s_lat'], 
     "longitude"=>$row['s_long'])); 
} 

echo json_encode (array('result'=> $arrayResult)); // <-- changed from $result 


mysqli_close($con);