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通過一些我已經peiced在一起了一些加密/解密方法是利用Rfc2898DeriveBytes
獲得密鑰和初始化向量的例子細算。我擔心接收我的加密內容的一方必須能夠解密它。由於我有過什麼樣的語言,但使用沒有控制權(可能成爲Java,PHP,C等。)我怎麼確保他們能夠獲得的密鑰和初始化向量(IV),因爲我已經使用在Rfc2898DeriveBytes
類。淨?這裏是我正在使用的加密和解密方法。跨平臺的加密/解密 - 處理密鑰和初始化向量(IV)
Public Shared Function EncryptText(ByVal plainText As String, ByVal password As String) As String
Dim aesCrypto As Rijndael = Nothing
Dim plainTextBytes As Byte()
plainTextBytes = Encoding.Default.GetBytes(plainText)
Dim rfc2898 As Rfc2898DeriveBytes
rfc2898 = New Rfc2898DeriveBytes(password, GenerateSalt(password))
aesCrypto = Rijndael.Create()
aesCrypto.Padding = PaddingMode.ISO10126
Dim tx As ICryptoTransform
tx = aesCrypto.CreateEncryptor(rfc2898.GetBytes(32), rfc2898.GetBytes(16))
Dim encryptedBytes As Byte()
encryptedBytes = tx.TransformFinalBlock(plainTextBytes, 0, plainTextBytes.Length)
Return Convert.ToBase64String(encryptedBytes)
End Function
Public Shared Function DecryptText(ByVal encryptedText As String, ByVal password As String) As String
Dim aesCrypto As Rijndael = Nothing
Dim encryptedTextBytes As Byte()
encryptedTextBytes = Convert.FromBase64String(encryptedText)
Dim rfc2898 As Rfc2898DeriveBytes
rfc2898 = New Rfc2898DeriveBytes(password, GenerateSalt(password))
aesCrypto = Rijndael.Create()
aesCrypto.Padding = PaddingMode.ISO10126
Dim tx As ICryptoTransform
tx = aesCrypto.CreateEncryptor(rfc2898.GetBytes(32), rfc2898.GetBytes(16))
Dim decryptedBytes As Byte()
decryptedBytes = tx.TransformFinalBlock(encryptedTextBytes, 0, encryptedTextBytes.Length)
Return Encoding.Default.GetString(decryptedBytes)
End Function
謝謝!這是我需要知道的。我將發送「salt」和加密文本。 – webworm 2011-03-29 12:05:07