意外地發現零，而展開一個可選值 - NSMutableURLRequest

Question

當我嘗試運行下面的代碼片段它的作品！

let urlWithParams = "http://192.168.0.4:3003/manager/all" 
    let request = NSMutableURLRequest(URL: NSURL(string: urlWithParams)!) 

但是，當我從Settings.bundle文本字段的字符串下面的代碼不起作用：

let webServer:String = NSUserDefaults().stringForKey("priceWeb")! 
    serverResponse.appendContentsOf(webServer) 
    serverResponse.appendContentsOf("/manager/all") 
    let request = NSMutableURLRequest(URL: NSURL(string: serverResponse)!) 

當我執行

print(webServer); 

輸出爲http://192.168.0.4:3003，當我執行

print(serverResponse); 

輸出http://192.168.0.4:3003/manager/all

但還是錯誤出現在以下行：

let request = NSMutableURLRequest(URL: NSURL(string: serverResponse)!) 

致命錯誤：意外發現零而展開的可選值

注：請提供所有快速回答

Answer 1

You must encode your url as it contains special characters.

試試這個

let urlWithParams = "http://192.168.0.4:3003/manager/all" 
let urlStr = urlWithParams.stringByAddingPercentEscapesUsingEncoding(NSUTF8StringEncoding)! // or use let urlStr = urlWithParams.stringByAddingPercentEncodingWithAllowedCharacters(.URLQ‌​ueryAllowedCharacter‌​Set()) 
let request = NSMutableURLRequest(URL: NSURL(string: urlStr)!) 

更多的參考看到蘋果Documents