的java比較多個值，並找到我需要找到最匹配的員工工資在數據庫記錄作爲最佳匹配

Question

：

Name: City:  State: 

A  (null) (null) 

A  (null) DEL 

(null) (null) (null) 

A  SAKET DEL 

比賽順序應該是：

NAME =名稱，狀態=州，城市=城市

2. NAME =名，STATE =州，城市= NULL

NAME =名稱，狀態= NULL，CITY = NULL

4. NAME = NULL，州= NULL，CITY = NULL

意味着如果在一排，所有屬性相符的 - 它應選擇，如果我們沒有那種數據，我們應該去下一個最好的選擇，如選擇州和城市爲NULL等

我的代碼如下，給我正確的結果，但我需要一個更高效辦法。

private static BigDecimal getsalaryForBestMatch(ResultSet results, EmployeeRq request) throws Exception{ 
    BigDecimal salary = null; 
    BigDecimal salaryWithState = null; 
    BigDecimal salaryWithName = null; 
    BigDecimal salaryWithNoMatch = null; 
    while (results.next()) { 

     String billerName = results.getString("EMP_NAME") != null ? results.getString("EMP_NAME").trim() : null; 
     String city = results.getString("CITY") != null ? results.getString("CITY").trim() : null; 
     String state = results.getString("STATE") != null ? results.getString("STATE").trim() : null; 

     BigDecimal salaryRslt = null; 

     if(results.getString("SALARY") != null){ 
      salaryRslt = BigDecimal.valueOf(results.getDouble("SALARY"));    
     } 
     if(billerName != null && !billerName.equals("") && billerName.equals(request.getBillPaymentsalaryCalculateInfo().getBillerName())){ 
      if(city != null && !city.equals("") && city.equals(request.getMsgRqHdr().getCity()) && 
        state != null && !state.equals("") && state.equalsIgnoreCase(request.getMsgRqHdr().getstate())){ 
       salary = salaryRslt; 
       break; 
      } else if((city == null || city.equals("")) && state != null && !state.equals("") && 
        state.equalsIgnoreCase(request.getMsgRqHdr().getState())){ 
       salaryWithState = salaryRslt;     
      } else if((city == null || city.equals("")) && (state == null || state.equals(""))){ 
       salaryWithName = salaryRslt;      
      } 
     } else if((billerName == null || billerName.equals("")) && (city == null || city.equals("")) && 
       (state == null || state.equals(""))){ 
      salaryWithNoMatch = salaryRslt;    
     } 
    } 

    if(salary != null){ 
     return salary; 
    } else if(salaryWithState != null){ 
     salary = salaryWithState; 
    } else if(salaryWithName != null){ 
     salary = salaryWithName; 
    } else if(salaryWithNoMatch != null){ 
     salary = salaryWithNoMatch; 
    } 

    return salary; 

} 

編輯：我不想使用3個額外的變量：salaryWithState，salaryWithName，salaryWithNoMatch。

Answer 1

我只想給出一般的想法如何實現，所以我沒有實際測試過，並檢查它是否會給你合適的薪水。

public BigDecimal getSalaryForBestMatch(ResultSet resultSet, PaymentSalaryInfo paymentSalaryInfo) { 
    Map<String, Supplier<String>> m1 = new HashMap<>(); 
    m1.put("EMP_NAME", paymentSalaryInfo::getBillerName); 
    m1.put("STATE", paymentSalaryInfo::getState); 
    m1.put("CITY", paymentSalaryInfo::getCity); 

    Map<String, Supplier<String>> m2 = new HashMap<>(); 
    m2.put("STATE", paymentSalaryInfo::getState); 
    m2.put("CITY", paymentSalaryInfo::getCity); 

    Map<String, Supplier<String>> m3 = new HashMap<>(); 
    m3.put("CITY", paymentSalaryInfo::getCity); 


    Optional<String> salary = Optional.empty(); 

    while(resultSet.next() && !salary.isPresent()) { 
     salary = apply(m1, resultSet); 
     //check salary and then apply(m2, resultSet) .... 
    } 

    return salary.isPresent() ? new BigDecimal(salary.get()) : null; 
} 


public Optional<String> apply(Map<String, Supplier<String>> filter, ResultSet resultSet) { 
    boolean allMatch = filter.entrySet().stream().allMatch(entry -> { 
     String value = resultSet.getString(entry.getKey()); 

     return value != null && value.equals(entry.getValue().get()); 
    }); 

    return allMatch ? Optional.of(resultSet.getString("salary")) : Optional.empty(); 
} 

Answer 2

我已經用不同的方式使用數組寫了相同的邏輯。如果您的環境可以使用數組，則可以使用此代碼。但我沒有測試過這些代碼。

private static BigDecimal getsalaryForBestMatch(ResultSet results, EmployeeRq request) throws Exception{ 
    BigDecimal salary = null; 
    int matchCount = 0; 
    String rBillerName = request.getBillPaymentsalaryCalculateInfo().getBillerName(); 
    String rCity = request.getMsgRqHdr().getCity(); 
    String rState = request.getMsgRqHdr().getstate(); 

    String [] truthArray = new String[] {rBillerName, rCity, rState}; 

    while (results.next()) { 
     String billerName = results.getString("EMP_NAME") != null ? results.getString("EMP_NAME").trim() : null; 
     String city = results.getString("CITY") != null ? results.getString("CITY").trim() : null; 
     String state = results.getString("STATE") != null ? results.getString("STATE").trim() : null; 
     BigDecimal salaryRslt = results.getString("SALARY") != null ? BigDecimal.valueOf(results.getDouble("SALARY")): null; 

     String [] testArray = new String[] {billerName, city, state}; 

     int localMatchCount = 0; 
     for(int i = 0; i < testArray.length; i++) { 
      if(testArray[i] != null && testArray[i].equals(truthArray[i])) 
       localMatchCount++; 
      else { 
       break; 
      } 
     } 

     if(localMatchCount >= matchCount){ 
      matchCount = localMatchCount; 
      salary = salaryRslt; 
     } 
    } 
    return salary; 
}