我正在爲mysql創建一個「DB」類。 DB類將與我的項目中的其他類彙總。PHP - 在mysql類DB中打開一個或多個連接?
的index.php
$db = new DB();
$fo = new Foo($db);
print_r($db->query("SELECT * FROM tbl"));
print_r($fo->testSelect());
Foo類
class Foo {
/**
* Constructor
* Aggregate class db object
*/
public function __construct(DB $db) {
$this->db = $db;
}
public function test() {
return $this->db->query("select * from tbl");
}
}
我的疑問是如何使用到數據庫的連接,使資源得到最佳利用。 在DB類中當我在構造函數中運行查詢(更新,選擇,...)或打開一次連接時,最好打開連接?
DB類(1)
if (!class_exists('DB')) {
class DB {
private function connect() {
$mysqli = new mysqli(DB_HOST, DB_USER, DB_PASS, DB_NAME, DB_PORT, DB_SOCKET);
if ($mysqli->connect_error) {
die("Connection failed: " . $mysqli->connect_errno . ' ' . $mysqli->connect_error);
} else {
$mysqli->set_charset(DB_CHARSET);
}
return $mysqli;
}
public function query($query) {
$db = $this->connect();
$result = $db->query($query);
while ($row = $result->fetch_array(MYSQLI_ASSOC)) {
$results[] = $row;
}
$result->free();
$db->close();
return $results;
}
..insert, update, delete function..
}
}
DB類(2)
if (!class_exists('DB')) {
class DB {
private mysqli;
public function __construct() {
$this->mysqli = new mysqli(DB_HOST, DB_USER, DB_PASS, DB_NAME, DB_PORT, DB_SOCKET);
if ($this->mysqli->connect_error) {
die("Connection failed: " . $this->mysqli->connect_errno . ' ' . $this->mysqli->connect_error);
} else {
$this->mysqli->set_charset(DB_CHARSET);
}
return $this->mysqli;
}
public function query($query) {
$result = $this->mysqli->query($query);
while ($row = $result->fetch_array(MYSQLI_ASSOC)) {
$results[] = $row;
}
$result->free();
return $results;
}
..insert, update, delete function..
public function __destruct() {
$this->mysqli->close();
}
}
}
哪個是正確/更好的解決方案? 謝謝
打開連接ONCE – RiggsFolly