如何從各個方面獲取每個存儲桶的最相關文檔ID？

Question

我如何才能獲得該方面中每個存儲桶的最相關文檔ID。 例如，我想知道桶「喜劇」，「戲劇」，「冒險」等最相關的文檔ID：

<results> 
    <status rid="v7r9hs8oFQqMHnk=" time-ms="3"/> 
    <hits found="85" start="0"> 
     <hit id="tt1411664"/> 
     <hit id="tt1911658"/> 
     <hit id="tt0086190"/> 
     <hit id="tt0120601"/> 
     <hit id="tt2141761"/> 
     <hit id="tt1674771"/> 
     <hit id="tt0056687"/> 
     <hit id="tt0397892"/> 
     <hit id="tt0258153"/> 
     <hit id="tt0796366"/> 
    </hits> 
    <facets> 
     <facet name="genres"> 
      <bucket value="Comedy" count="41"/> <<???? What is the most relevant document ID for this bucket? 
      <bucket value="Drama" count="35"/> <<???? What is the most relevant document ID for this bucket? 
      <bucket value="Adventure" count="29"/> <<???? What is the most relevant document ID for this bucket? 
      <bucket value="Sci-Fi" count="24"/> <<???? What is the most relevant document ID for this bucket? 
      <bucket value="Action" count="20"/> <<???? What is the most relevant document ID for this bucket? 
     </facet> 
    </facets> 
</results> 

Answer 1

你必須讓每方面一個查詢。指定小的過濾查詢，例如：

fq=genres:'Comedy'&size=1

看一看的文檔使用方面的信息： http://docs.aws.amazon.com/cloudsearch/latest/developerguide/faceting.html