爲什麼我的「For」語句被忽略？以及如何解決它？

Question

在每個「Elif或Else」語句之後，Python完全忽略了「For statemnt」，我已經通過在其中放置了打印行來調試它，沒有打印任何內容，我在for語句和Elif語句內部打印行，打印的東西，我一直在尋找，我不知道該怎麼做。

爲什麼我的「for」語句被忽略？以及如何修復它/

def horizental_checker(lst1,lst2,lst3,lst4,place_checker,lst5=[],lst6=[],lst7=[]):  #place_checker checks if the lst is before the fourth column 
count = 0 
if place_checker == 1 or place_checker == 20: 
    for a,b,c,d in zip(lst1,lst2,lst3,lst4): 
     a = int(a) 
     b = int(b) 
     c = int(c) 
     d = int(d) 
     return (a * b * c * d) 
elif place_checker == 2 or place_checker == 19: 
    print "TESSSSSST" 

    for e,a,b,c,d in zip(lst5,lst1,lst2,lst3,lst4): 
     print a,b,c,d,e 
     a = int(a) 
     b = int(b) 
     c = int(c) 
     d = int(d) 
     e = int(e) 
     count = (a * b * c * d) 
     print "my count is %i" % count 
     if (e * a * b * c) > count: 
      count = (e * a * b * c) 
      print "my second count is %i" % count 
     return count 

elif place_checker == 3 or place_checker == 18: 
    for e,f,a,b,c,d in zip(lst5,lst6,lst1,lst2,lst3,lst4): 
     a = int(a) 
     b = int(b) 
     c = int(c) 
     d = int(d)  
     count = (a * b * c * d) 
     if (e * a * b * c) > count: 
      count = (e * a * b * c) 
     if (f * e * a * b) > count: 
      count = (f * e * a * b) 
     return count   
else: 
    for e,f,g,a,b,c,d in zip(lst5,lst6,lst7,lst1,lst2,lst3,lst4): 
     a = int(a) 
     b = int(b) 
     c = int(c) 
     d = int(d)  
     count = (a * b * c * d) 
     if (e * a * b * c) > count: 
      count = (e * a * b * c) 
     if (f * e * a * b) > count: 
      count = (f * e * a * b) 
     if (g * f * e * a) > count: 
      count = (g * f * e * a) 
     return count 

Answer 1

什麼是zip（...）返回？如果主體返回空列表，它將不會執行任何操作。打印出zip（...）在for之前返回的內容。