2016-01-20 51 views
1

在我的laravel應用程序我有一個數據庫列travel_date類型date。此列已添加到Eloquent-Model類的$dates屬性中。但是,如果我給你的價值22.01.2015到模型碳拋出異常

InvalidArgumentException in Carbon.php line 425: Unexpected data found. 
Unexpected data found. 
Data missing 

in Carbon.php line 425 
at Carbon::createFromFormat('Y-m-d H:i:s', '20.01.2016') in Model.php line 3015 
at Model->asDateTime('20.01.2016') in Model.php line 2971 
at Model->fromDateTime('20.01.2016') in Model.php line 2926 
at Model->setAttribute('travel_date', '20.01.2016') in Model.php line 446 
[...] 

我的代碼來創建模式是:

$trip = Trip::create(array_merge($request->all(), ['carpool_id' => $carpool->id])); //travel_date is 20.01.2016 

而且我$dates,物業

protected $dates = ['deleted_at', 'travel_date']; 

感謝的問候!

+0

日期性能預計將在'Y-M-d H:我:s'格式。所以只需將它們保存爲這種格式,一切都會好的。 –

回答

1

您可以創建您的行程是這樣的:

$trip = new Trip(); 
$trip->property_1 = $request->property_1; 
$trip->property_2 = $request->property_2; 
$trip->carpool_id = $carpool->id; 
$trip->travel_date = Carbon::createFromFormat('d.m.Y', '20.01.2016'); 
$trip->save();