SQL查詢來計算奇數和偶數的位數總和

Question

我需要一個SQL查詢/函數，它將找出數位的總和，它出現在偶數位置和數字的總和位於奇數位置。

實施例：

如果號碼是440065385：

x=4+0+6+3+5=18(x is holding sum of odd positions) 
y=4+0+5+8=17 (y holds the sum of even positions). 

感謝。

Answer 1

可以使用水平模仿迭代並連接通過以達到相同的

with iterate as 
(select level as i from dual connect by level <=25) 
select 
     table1.column1, 
     sum(decode(mod(iterate.i,2),0,substr(table1.column1,iterate.i,1))) sum_even, 
     sum(decode(mod(iterate.i,2),1,substr(table1.column1,iterate.i,1))) sum_old 
from table1 ,iterate 
where iterate.i <=length(table1.column1) 
group by table1.column1 

Answer 2

你可以用數字表加入你的表格，將所有數字拆分成若干行，然後分別計算賠率和位置數字。

with positions(position) as 
    (select level from dual connect by level <=25 
    ), 
digits as 
    (
    select 
     t1.v, 
     n.position , 
     cast(substr(t1.v ,length(t1.v) - n.position + 1, 1) as int) as digit 
    from my_table t1 left join positions n 
    on n.position <= length(t1.v) 
    ) 
select 
    v, 
    sum(case when mod(position,2)=0 then digit else 0 end) as evensum, 
    sum(case when mod(position,2)=1 then digit else 0 end) as oddsum 
from 
    digits 
group by 
    v 

測試Sql Fiddle，結果：

V   EVENSUM ODDSUM 
440065385 17  18