pymysql迭代

Question

迭代每條記錄的獲取數據，然後通過按鍵就什麼都不顯示打印

#!/usr/bin/env python 

# Print necessary headers. 
print("Content-Type: text/html") 
print() 

import pymysql.cursors 
# Connect to the database. 
import pymysql 
conn = pymysql.connect(db='candidate', user='root',passwd='123',host='localhost') 
print ("connect successful!!") 
c = conn.cursor() 
c.execute("SELECT can_id,can_name,state,total_votes FROM voting") 
result_set = c.fetchall() 
for row in result_set: 
    print(row["can_id"]) 

打印（行）正常工作

Answer 1

c = conn.cursor(pymysql.cursors.DictCursor) 

或

conn = pymysql.connect(db='candidate', user='root', passwd='123', host='localhost', cursorclass=pymysql.cursors.DictCursor) 

Answer 2

我建議使用一些變化PyMySQL documentation作爲參考：

#!/usr/bin/env python 
# -*- conding: utf-8 -*- 
# Print necessary headers. 
print("Content-Type: text/html") 
import pymysql.cursors 
# Connect to the database. 
# That is important: the order of connection parameters 
# 1st host, 2nd user, ... 
conn = pymysql.connect(
    host='localhost' 
    user='root', 
    password='123', 
    db='candidate', 
    cursorclass=pymysql.cursors.DictCursor # <-- declare cursor class 
) 
print ("connect successful!!") 
try: 
    with conn.cursor() as c: 
     query = "SELECT can_id, can_name, state, total_votes FROM voting;" 
     c.execute(query) 
    with c as pointer: 
     for row in pointer.fetchall(): 
      print("Name: %s" % row['can_name']) 
finally: 
    conn.close()