我有一本字典 dicto = {12:{34:45,56:78},45:{67:23,90:15}}
我想刪除一個鍵值對說dictionary.How的關鍵45的67:23做呢? 這是我做的,到目前爲止,但我得到的錯誤 dicto = {12:{34:45,56:78},45:{67:23,90:15}}
for k,v in dicto.items():
for i in v.k
內印刷字典鍵我有這樣的下面的代碼: d = {'one' : '11111111', 'two' : '01010101', 'three' : '10101010'}
string = '01010101 11111111 10101010'
text = ''
for key, value in d.items():
if value in string:
t
該程序試圖在文件中打印最常用的10個單詞。但我無法打印的10個最常用的詞 from string import *
file = open('shakespeare.txt').read().lower().split()
number_of_words = 0
onlyOneWord = []
for i in file:
if i in onlyOneWord: con