從Laravel返回數據whereHas查詢

我將如何去返回數據從companywhereHas子查詢？從Laravel返回數據whereHas查詢

$data = Job::where('active','=','1') 
    ->whereHas('company', function($q) use ($distance_select) { 
     $q->where('active','=','1') 
     ->select(DB::raw($distance_select)) 
      ->whereHas('user', function($q) { 
       $q->whereHas('group', function ($q) { 
        $q->whereIn('group.name_short', array('admin', 'moderator', 'subscriber')); 
       }); 
      }); 
    });

我從Job模型中獲取所有數據。我的原始查詢返回company子查詢中的distance值。

這是對那些感興趣的子查詢。

if ($units == 'miles') { 
    $gr_circle_radius = 3959; 
} elseif ($units == 'kilometers') { 
    $gr_circle_radius = 6371; 
} 

$distance_select = sprintf(
    " 
     ROUND((%d * acos(cos(radians(%s)) " . 
    " * cos(radians(lat)) " . 
    " * cos(radians(lng) - radians(%s)) " . 
    " + sin(radians(%s)) * sin(radians(lat)) " . 
    ") " . 
    ") 
         , 2) " . 
    "AS distance 
         ", 
    $gr_circle_radius, 
    $lat, 
    $lng, 
    $lat 
);

一切正常，我只是希望能夠訪問distance在子查詢返回。

------------ ------------添加

這裏是原始查詢

select * from `job` where `active` = '1' and (select ROUND((3959 * acos(cos(radians(38.15499960)) * cos(radians(lat)) * cos(radians(lng) - radians(-85.66808610)) + sin(radians(38.15499960)) * sin(radians(lat)))) , 2) AS distance from `company` where `job`.`company_id` = `company`.`id` and `active` = '1' and (select count(*) from `users` where `company`.`user_id` = `users`.`id` and (select count(*) from `group` inner join `group_user` on `group`.`id` = `group_user`.`group_id` where `group_user`.`user_id` = `users`.`id` and `group`.`name_short` in ('admin', 'moderator', 'subscriber')) >= 1 and `users`.`deleted_at` is null) >= 1) >= 1 limit 10

來源

2015-02-09 Jesse Szypulski

想通了的輸出經過數小時和數小時的研究。

這裏是新的，工作代碼

$data = Job::where('job.active','=',1) 
    ->select(DB::raw("`job`.*, `company`.`lat` as `lat`, `company`.`lng` as `lng`, ROUND((? * acos(cos(radians(?)) * cos(radians(`lat`)) * cos(radians(`lng`) - radians(?)) + sin(radians(?)) * sin(radians(`lat`)) )) , 2) AS `distance`")) 
    ->leftJoin('company', function($join) { 
     $join->on('job.company_id', '=', 'company.id'); 
    }) 
    ->setBindings([$radius, $lat, $lng, $lat], 'select') 
    ->whereHas('company', function($q) { 
     $q->where('active','=',1) 
     ->whereHas('user', function($q) { 
      $q->whereHas('group', function ($q) { 
       $q->whereIn('group.name_short', array('admin', 'moderator', 'subscriber')); 
      }); 
     }); 
    });

這裏是爲那些有興趣

select `job`.*, `company`.`lat` as `lat`, `company`.`lng` as `lng`, ROUND(('3959' * acos(cos(radians('38.15499960')) * cos(radians(`lat`)) * cos(radians(`lng`) - radians('-85.66808610')) + sin(radians('38.15499960')) * sin(radians(`lat`)) )) , 2) AS `distance` from `job` left join `company` on `job`.`company_id` = `company`.`id` where `job`.`active` = '1' and (select count(*) from `company` where `job`.`company_id` = `company`.`id` and `active` = '1' and (select count(*) from `users` where `company`.`user_id` = `users`.`id` and (select count(*) from `group` inner join `group_user` on `group`.`id` = `group_user`.`group_id` where `group_user`.`user_id` = `users`.`id` and `group`.`name_short` in ('admin', 'moderator', 'subscriber')) >= 1 and `users`.`deleted_at` is null) >= 1) >= 1 limit 10

原始查詢

來源

2015-02-13 03:26:04

從Laravel返回數據whereHas查詢

回答

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