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我想我的用戶發送到服務器,並獲得一個長的數字作爲響應,但我得到了客戶400錯誤,並得到這個exeption在服務器端:無法反序列化對象的實例進行START_ARRAY令牌
nested exception is com.fasterxml.jackson.databind.JsonMappingException: Can not deserialize instance of mashfood.model.User out of START_ARRAY token
我的客戶的suser模型爲服務器用戶模式完全一樣:
的suser(或用戶):
class User{
public long id;
public String username;
public String password;
public String firstName;
public String lastName;
public String gender;
public String nationalNumber;
public String phoneNumber;
public String address;
public String email;
public boolean isLoggedIn;
public String imageUrl;
public int areaNumber;
}
客戶端連接到服務器是這樣的: ** tClass是響應 **則params的類型[0]是用戶,我要發送到服務器 ** URL +條件方法的網址手柄獲取用戶
protected ResponseHandler doInBackground(Object... params) {
try {
serverResponse=new ServerResponse();
result = restTemplate.postForObject(URL + conditions, params,tClass);
serverResponse.singleResult=result;
serverResponse.isReady=true;
responseHandler.onServerRespond(serverResponse);
}catch (Exception e){
serverResponse.isReady=false;
serverResponse.message=e.getMessage();
e.printStackTrace();
}
return responseHandler;
}
和服務器端代碼:
@RequestMapping(value = "/register",method = RequestMethod.POST)
@ResponseBody
public Long registerNewUser(@RequestBody User user){
if(user!=null){
try {
System.out.println("REGISTER "+ user==null);
SessionFactory sessionFactory=HibenateConnection.connectingHibernate();
Session session=sessionFactory.openSession();
session.beginTransaction();
session.save(user);
session.getTransaction().commit();
User user1=getUser(user.username);
session.close();
return user1.id;
}catch (Exception e){
e.printStackTrace();
}
}
return -1l;
}
和我的輸出JSON是:
[{
"address": "",
"areaNumber": 0,
"email": "email",
"firstName": "name",
"gender": "male",
"id": -1,
"imageUrl": "img",
"isLoggedIn": false,
"lastName": "lastn",
"nationalNumber": "898898",
"password": "pass",
"phoneNumber": "936",
"username": "mehdi"
}]
哪裏是我的問題嗎?
你能請張貼JSON字符串? – Bhokal
@Bhokal是的,我加入了我的問題 –
爲什麼這個投票結果作爲題外話?它包含一個MCVE。 –