強制密碼要求

Question

我要檢查用戶是否已經成功地滿足了以下要求：

• 的密碼至少爲8個字符
• 由一個資本&一個小寫字母的

我將如何做到這一點？

我使用下面的PHP腳本：

if (strlen($password) < 8) { 
    false 
} else { 
    if (preg_match("/[^0,9]/", $password)) { 
    // how to check the upper case and lower case 
    } 
} 

Answer 1

使用preg_match("/[A-Z]/")和preg_match("/[a-z]/")

Answer 2

preg_match('/[a-z]/', $password) && preg_match('/[A-A]/', $password) 

Answer 3

if (
    strlen($password) >= 8) && 
    preg_match('/[A-Z]/', $password) > 0 && 
    preg_match('/[a-z]/', $password) > 0) 
{ 
    /* Password validation passes, do stuff. */ 
} 
else { 
    /* Password validation fails, show error. */ 
} 

Answer 4

if(strlen($password) < 8) { 
    return false; 
} 
if(preg_match("/[^0,9]/", $password)) { 
    how to check the upper case and lower case 
} 
if($password == strtoupper($password) || $password == strtolower($password)){ 
//pass fails because its either all upcase, or lowercase 
} 

Answer 5

您可以使用trim，這實際上是比正則表達式

更快

if (trim($password, 'a..z') != '' && trim($password, 'A..Z') != '' && strlen($password) >= 8) 
{ 
    /* Password validation passes, do stuff. */ 
} 
else { 
    /* Password validation fails, show error. */ 
} 

Answer 6

你可以做到這一點與正則表達式：

if (!preg_match('/^(?=[a-z])(?=[A-Z])[a-zA-Z]{8,}$/', $password)) 
{ 
    //error 
} 

Answer 7

你可以使用一個密碼排位技術：

$x = "a12ASD!@#$"; 
$rank = Array(); 


$rank['length'] = strlen($x); 

$matches = Array(); 
preg_match_all("/([a-z]+)/", $x, $matches); 
$rank['lowercase'] = strlen(implode('', $matches[0]))/count($matches[0]); 

$matches = Array(); 
preg_match_all("/([A-Z]+)/", $x, $matches); 
$rank['uppercase'] = strlen(implode('', $matches[0]))/count($matches[0]); 

$matches = Array(); 
preg_match_all("/([0-9]+)/", $x, $matches); 
$rank['numbers'] = strlen(implode('', $matches[0]))/count($matches[0]); 

$matches = Array(); 
preg_match_all("/([^a-zA-Z0-9]+)/", $x, $matches); 
$rank['symbols'] = strlen(implode('', $matches[0]))/count($matches[0]); 


echo "<pre>"; 
var_dump($rank); 
echo "</pre>";