出於某種原因,我的文件上傳腳本工作不正常,我完全不知道爲什麼:?該腳本設法發送文件,但我無法跟蹤進度或狀態更改。我試圖評論出不必要的位進行調試,但它仍然不起作用。XMLHTTPRequest事件偵聽器不工作?
如果有人能指出我的錯誤,我將永遠感激,給你一個虛擬的cookie
$('#submit').click(function(e){
e.preventDefault();
$('#progressContainer').slideDown(10);
var f = document.getElementById('file'),
pb = document.getElementById('pb'),
pt = document.getElementById('pt');
app.uploader({
files:f,
progressBar:pb,
progressText:pt,
processor:'scripts/php/upload.php',
finished: function(){
$('#pt').html("Upload complete");
},
error: function(){
$('#pt').html("Upload Error, please try again");
}
});
});
var app = app || {};
(function(o){
"use strict"
var ajax, getFormData, setProgress;
ajax = function(data){
var xmlhttp = new XMLHttpRequest(), uploaded;
xmlhttp.addEventListener('readystatechange', function(){
if(this.readystate === 4){
if(this.status === 200){
//uploaded = JSON.parse(this.response);
//if(typeof o.options.finished === 'function'){
o.options.finished();
//}
} else {
//if(typeof o.options.error === 'function'){
o.options.error();
//}
}
}
});
xmlhttp.upload.addEventListener('progress', function(event){
var percent;
//if(event.lengthComputable === true){
percent = math.round(event.loaded/event.total * 100);
setProgress(percent);
alert(percent)
//}
});
xmlhttp.open('POST', o.options.processor);
xmlhttp.send(data);
}
getFormData = function(src){
var data = new FormData(), i;
for(i=0;i<src.length;i++){
data.append('file[]',src[i]);
}
data.append('formSent',true);
return data;
}
setProgress = function(val){
$('#pb').animate({width:val+"%"},10);
$('#pt').html(val+"%");
}
o.uploader = function(opt){
o.options = opt;
if(o.options.files !== undefined){
ajax(getFormData(o.options.files.files));
}
}
}(app));
控制檯上的任何錯誤? –
〜 - 〜。我把「math.round」而不是'Math.round'......我現在覺得很蠢,這已經讓我煩惱了好幾個小時,而且我太固執,不能檢查錯誤控制檯。謝謝馬文Medeiros :) –