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我正試圖用變量中的數據填充下拉菜單。這是我迄今爲止所做的,並且不起作用。我究竟做錯了什麼?使用數組填充下拉列表
<script>
$(function() {
$('#dropdownMenu1').click(function() {
var director_names = {"director_name": ["Aaron Schneider", "Aaron Seltzer", "Abel Ferrara", "Adam Goldberg", "Adam Marcus", "Adam McKay", "Adam Rapp", "Adam Rifkin", "Adam Shankman", "Adrian Lyne", "Adrienne Shelly", "Agnieszka Holland", "Agnieszka Wojtowicz-Vosloo", "Akiva Goldsman", "Akiva Schaffer", "Alan Cohn", "Alan J. Pakula", "Alan Metter", "Alan Parker", "Alan Poul", "Alan Rudolph", "Alan Shapiro", "Alan Taylor"]};
var myDDL = document.getElementById("dropdownMenu1");
var i;
for (i = 0; i < director_names.director_name.length; i++) {
var option = document.createElement("option");
option.text = director_names.director_name[i].name;
option.value = director_names.director_name[i].address;
try {
myDDL.options.add(option);
}
catch (e) {
alert(e);
}
}
});
});
</script>
你的json不包含'name'和'address' ..它是一個字符串數組,所以你只能在'option'的'value'和'text'中使用'director_names.director_name [i]'' 。 –
這是無效的JavaScript;我假設這是因爲在關閉'script'標籤之前已經刪除了一些內容...... var director_names:{「...」};'行不符合你的想法,你需要使用一個'='爲變量賦值。使用這樣的':',它被解釋爲[標籤](https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Statements/label)。有[在這個問題沒有JSON](http://stackoverflow.com/questions/2904131/what-is-the-difference-between-json-and-object-literal-notation),只有一個對象文字,你認爲是JSON。 –