我有兩個查詢將數據插入到它們各自的表中。這工作正常。我一直試圖做的是在執行每個查詢後獲取lastInsertId並將這些值插入第三個表中。但是,當我檢查數據庫時,輸入值0。兩個表都有一個自動遞增的字段。你能告訴我的代碼爲什麼發生或有任何建議嗎?我相對較新的PHP,所以如果你注意到我編碼的方式是不整潔的,特別是在我執行查詢的最後,請告訴我。我會很感激。pdo lastInsertId()總是返回0
if ($oneWay)
{
$query = "INSERT INTO journey
(from_destination,to_destination,journey_type,depart_date,depart_time,seats_available,journey_message,user_type)
VALUES('$pjFrom','$pjTo','$radioJourneyType', STR_TO_DATE('$departDate','%d/%m/%Y'),'$newDepTime','$seatcounter','$textareanotes','$radUserType')";
$userID = "SELECT user_id FROM `user` ORDER BY journey_id DESC LIMIT 1";
}
else
{
$query = "INSERT INTO journey
(from_destination,to_destination,journey_type,depart_date,depart_time,return_date,return_time,seats_available,journey_message,user_type)
VALUES('$pjFrom','$pjTo','$radioJourneyType', STR_TO_DATE('$departDate','%d/%m/%Y'),'$newDepTime',STR_TO_DATE('$returnDate','%d/%m/%Y'),'$newRetTime ','$seatcounter','$textareanotes','$radUserType')";
//$userID = "SELECT user_id FROM `user` ORDER BY journey_id DESC LIMIT 1";
}
$queryfb = "INSERT INTO user
(facebook_id,facebook_username,facebook_first_name,facebook_last_name,facebook_image,facebook_link)
VALUES('$hdnFacebookId','$hdnUsername','$hdnFirstName','$hdnLastName','$hdnFacebookImg','$hdnFacebookUrl')";
//$journeyID = "SELECT journey_id FROM `journey` ORDER BY journey_id DESC LIMIT 1";
$queryUserJourney = "INSERT INTO user_journey
(user_id,journey_id)
VALUES('$lastUserID','$lastJourneyID')";
$db->exec($query);
$lastUserID = $db->lastInsertId();
$db->exec($queryfb);
$lastJourneyID = $db->lastInsertId();
$db->exec($queryUserJourney);//problem: 0 values being entered???
}
更新
$db->exec($query);
$lastUserID = $db->lastInsertId();
$db->exec($queryfb);
$lastJourneyID = $db->lastInsertId();
$queryUserJourney = "INSERT INTO user_journey
(user_id,journey_id)
VALUES('$lastUserID','$lastJourneyID')";
$db->exec($queryUserJourney);working thanks to jmadsen
PHP的字符串插值不起作用,因爲你相信它的確如此。您不能僅僅替換用於組成字符串的變量,並期望字符串發生更改。 – Maerlyn 2013-04-07 22:32:53