Java，使用迭代器搜索ArrayList並刪除匹配的對象

Question

基本上，用戶提交一個迭代器搜索ArrayList的字符串。當發現迭代器將刪除包含該字符串的對象。

因爲這些對象中的每一個都包含兩個字符串，所以我很難將這些行寫成一行。

Friend current = it.next(); 
String currently = current.getFriendCaption(); 

感謝您的幫助！

Answer 1

你不需要他們在同一行，只需使用remove當它匹配刪除項目：

Iterator<Friend> it = list.iterator(); 
while (it.hasNext()) { 
    if (it.next().getFriendCaption().equals(targetCaption)) { 
     it.remove(); 
     // If you know it's unique, you could `break;` here 
    } 
} 

完整的示例：

import java.util.*; 

public class ListExample { 
    public static final void main(String[] args) { 
     List<Friend> list = new ArrayList<Friend>(5); 
     String   targetCaption = "match"; 

     list.add(new Friend("match")); 
     list.add(new Friend("non-match")); 
     list.add(new Friend("match")); 
     list.add(new Friend("non-match")); 
     list.add(new Friend("match")); 

     System.out.println("Before:"); 
     for (Friend f : list) { 
      System.out.println(f.getFriendCaption()); 
     } 

     Iterator<Friend> it = list.iterator(); 
     while (it.hasNext()) { 
      if (it.next().getFriendCaption().equals(targetCaption)) { 
       it.remove(); 
       // If you know it's unique, you could `break;` here 
      } 
     } 

     System.out.println(); 
     System.out.println("After:"); 
     for (Friend f : list) { 
      System.out.println(f.getFriendCaption()); 
     } 

     System.exit(0); 
    } 

    private static class Friend { 
     private String friendCaption; 

     public Friend(String fc) { 
      this.friendCaption = fc; 
     } 

     public String getFriendCaption() { 
      return this.friendCaption; 
     } 

    } 
} 

輸出：

$ java ListExample 
Before: 
match 
non-match 
match 
non-match 
match 

After: 
non-match 
non-match