2017-04-16 138 views
0

我試圖從postgresql數據庫獲取數據,我得到的錯誤:pg_last_error()期望參數1是資源,在/path/to/query.php中給出的對象 所以數據是作爲一個對象而不是資源。任何想法如何解決這一問題?pg_query拋出一個錯誤

的SQL工作與此代碼:

foreach ($conn->query($sql1) as $row) 
{ 
print $row["Site_ID"] . " "; 
print $row["Site_name_1"] . "<br /> "; 

} 

但問題棱當我使用pg_query代替。
這裏是我的代碼:

<?php include 'header.php'; ?> 
<div class='container'> 
<?php include 'menu.php'; ?> 
<?php include 'PDO_connect.php'; ?> 

<?php 

$sql1='SELECT "Site_ID", "Site_name_1" FROM "Sites" ORDER BY "Sites"."Site_ID" ASC'; 

$result1 = pg_query($conn,$sql1); 
if(!$result1) { 
    echo "There is an error!"; 
    echo pg_last_error($conn); 
} 
?> 

我的連接信息

<?php 
try { 
$dbuser = 'usr'; 
$dbpass = 'pwd'; 
$host = "localhost"; 
$dbname="db"; 

$conn = new PDO('pgsql:host=localhost;dbname=db', $dbuser, $dbpass); 
}catch (PDOException $e) { 
echo "Error : " . $e->getMessage() . "<br/>"; 
die(); 
} 
?> 
+0

你能顯示'$ conn'的聲明?你可以用var_dump($ var)檢查它的值。它應該是pg_connect返回的資源:http://php.net/manual/en/function.pg-connect.php – JSLirola

+0

var_dump($ conn)returns:object(PDO)#1(0){} –

+1

我認爲您正在將PDO與pg_ *方法混合,如果您使用PDO進行連接,則應使用[PDO功能](http://php.net/manual/en/class.pdo.php)。檢查這個類似的問題:http://stackoverflow.com/questions/16108784/connect-to-postgresql-using-pdo – JSLirola

回答

0

正如評論說我是混合PDO和pg_connect,這解決了我的問題:

<?php 
$servername = "localhost"; 
$username = "usr"; 
$password = "pwd"; 
$database = "db"; 
?> 

<?php 
    $conn = pg_connect("host=localhost dbname=$database user=$username password=$password")or die("Can't connect to database".pg_last_error()); 
?>