到目前爲止,我編寫了一個代碼從ftp服務器下載文件,然後使用第三方dll(媒體信息)獲取有關文件的元數據詳細信息。直到這很好,現在我試圖根據輸出生成xml文件,我在這裏看到了很好的例子How can I build XML in C#?來生成xml,但是我的場景有點不同,這就是爲什麼我創建了這個線程。從輸出生成xml文件
下面是代碼即可獲得JPG文件的屬性值
static void Main(string[] args)
{
try
{
string file = "test.jpg";
FtpWebRequest reqFTP;
string ftpserverIp = "1.0.0.1";
string fileName = @"c:\downloadDir\" + file;
FileInfo downloadFile = new FileInfo(fileName);
FileStream outputStream = new FileStream(fileName, FileMode.Append);
reqFTP = (FtpWebRequest)FtpWebRequest.Create(new Uri("ftp://" + ftpserverIp + "/" + file));
reqFTP.Method = WebRequestMethods.Ftp.DownloadFile;
reqFTP.UseBinary = true;
reqFTP.KeepAlive = false;
reqFTP.Timeout = -1;
reqFTP.UsePassive = true;
reqFTP.Credentials = new NetworkCredential("sh", "SE");
FtpWebResponse response = (FtpWebResponse)reqFTP.GetResponse();
Stream ftpStream = response.GetResponseStream();
long cl = response.ContentLength;
// reqFTP.Method = WebRequestMethods.Ftp.ListDirectory;
int bufferSize = 4096;
int readCount;
byte[] buffer = new byte[bufferSize];
readCount = ftpStream.Read(buffer, 0, bufferSize);
Console.WriteLine("Connected: Downloading File");
while (readCount > 0)
{
outputStream.Write(buffer, 0, readCount);
readCount = ftpStream.Read(buffer, 0, bufferSize);
Console.WriteLine(readCount.ToString());
}
ftpStream.Close();
outputStream.Close();
response.Close();
Console.WriteLine("Downloading Complete");
var message = new StringBuilder();
ConsoleApplication2.Program TechMeta = new ConsoleApplication2.Program();
TechMeta.PutMessage(file, message);
Console.WriteLine(message);
}
catch (Exception ex)
{
Console.Write(ex);
}
}
private void PutMessage(string filename, StringBuilder message)
{
//Check the file is video or Image file here
string extension =".jpg";
bool b;
if (b = filename.Contains(extension))
{
HowToUse_Dll.ImageInterrogator imageInterrogator = new HowToUse_Dll.ImageInterrogator();
imageInterrogator.LoadFile(filename);
message.AppendFormat(messageFormat, "Width", imageInterrogator.GetWidth(), Environment.NewLine);
message.AppendFormat(messageFormat, "Height", imageInterrogator.GetHeight(), Environment.NewLine);
message.AppendFormat(messageFormat, "FileSize", imageInterrogator.GetFileSize(), Environment.NewLine);
message.AppendFormat(messageFormat, "FileFormat", imageInterrogator.GetFileFormat(), Environment.NewLine);
message.AppendFormat(messageFormat, "Resolution", imageInterrogator.GetResolution(), Environment.NewLine);
}
else
{
HowToUse_Dll.VideoInterrogator videoInterrogator = new HowToUse_Dll.VideoInterrogator();
videoInterrogator.LoadFile(filename);
message.AppendFormat(messageFormat, "FileSize", videoInterrogator.GetFileSize(), Environment.NewLine);
message.AppendFormat(messageFormat, "Duration", videoInterrogator.GetDuration(), Environment.NewLine);
message.AppendFormat(messageFormat, "AspectRatio", videoInterrogator.GetAspectRatio(), Environment.NewLine);
message.AppendFormat(messageFormat, "GetAspectRatio", videoInterrogator.GetAspectRatio(), Environment.NewLine);
message.AppendFormat(messageFormat, "BitRate", videoInterrogator.GetBitRate(), Environment.NewLine);
message.AppendFormat(messageFormat, "Format", videoInterrogator.GetFormat(), Environment.NewLine);
message.AppendFormat(messageFormat, "VideoCoder", videoInterrogator.GetVideoCoder(), Environment.NewLine);
message.AppendFormat(messageFormat, "Redirector", videoInterrogator.GetRedirector(), Environment.NewLine);
message.AppendFormat(messageFormat, "TargetPlayback", videoInterrogator.GetTargetPlayback(), Environment.NewLine);
}
}
public string messageFormat
{
get
{
return "{0}: {1}{2}";
}
}
基座上的test.jpg放在文件它,TechMeta.PutMessage(文件,消息); 消息值
{Width: 1024
Height: 576
FileSize: 84845
FileFormat: JPEG
Resolution: 8
}
現在正嘗試基於像下面的值生成XML文件時,更重要的是我想基於像下面
<image Name="test.jpg">
<width>1024</width>
<height>576</height>
<file-Size>84845</file-Size>
<resolution>8</resolution>
<image Name="test1.jpg">
<width>1024</width>
<height>576</height>
<file-Size>84845</file-Size>
<resolution>8</resolution>
任何建議新文件
追加請
你試過了什麼?我們不是在這裏爲你寫代碼。如果您遇到困難,我們可以幫助您,但您必須告訴我們您的問題到底是什麼。 – svick 2012-02-07 06:44:10
@svick不期待有人爲我編寫代碼,期待有人建議從我的輸出中生成xml的更好或最好的方法,例如生成xsd文件或使用xmldocument等。bcoz在xml中使用不多或專家。這就是爲什麼我在這裏拋出這個問題 – Usher 2012-02-07 07:08:29
你想要一個「更好的方式」,但你不會說比什麼更好。先嚐試一下,然後問我們是否不起作用,或者你認爲應該有更好的方法。此外,您的XML無效,您永遠不會關閉''元素,並且XML似乎有多個根元素。 –
svick
2012-02-07 07:17:11