我有一個應用程序,其中有一個包含用戶名和密碼的登錄表單。當用戶輸入用戶名和密碼時,應驗證其用戶名和密碼從服務器API數據庫,如果他是一個有效的用戶,他應該作出登錄。 我已經做下面的代碼後在該方法我解析從API服務器接收到的JSON響應和結合&插入SQLite數據庫通過服務器API數據庫如何從服務器數據庫檢查用戶名和密碼,並在iphone中顯示新頁面
-(void)sendRequest
{
UIDevice *device = [UIDevice currentDevice];
NSString *udid = [device uniqueIdentifier];
NSString *sysname = [device systemName];
NSString *sysver = [device systemVersion];
NSString *model = [device model];
NSLog(@"idis:%@",[device uniqueIdentifier]);
NSLog(@"system nameis :%@",[device systemName]);
NSLog(@"System version is:%@",[device systemVersion]);
NSLog(@"System model is:%@",[device model]);
NSLog(@"device orientation is:%d",[device orientation]);
NSString *post = [NSString stringWithFormat:@"Loginkey=%@&Password=%@&DeviceCode=%@&Firmware=%@&IMEI=%@",txtUserName.text,txtPassword.text,model,sysver,udid];
NSData *postData = [post dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES];
NSString *postLength = [NSString stringWithFormat:@"%d", [postData length]];
NSLog(@"%@",postLength);
NSMutableURLRequest *request = [[[NSMutableURLRequest alloc] init] autorelease];
[request setURL:[NSURL URLWithString:@"http://192.168.0.68:91/JourneyMapperAPI?RequestType=Login"]];
[request setHTTPMethod:@"POST"];
[request setValue:postLength forHTTPHeaderField:@"Content-Length"];
[request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"];
[request setHTTPBody:postData];
NSURLConnection *theConnection = [[NSURLConnection alloc] initWithRequest:request delegate:self];
if (theConnection) {
webData = [[NSMutableData data] retain];
NSLog(@"%@",webData);
}
else
{
}
}
的登錄信息。
-(void)connectionDidFinishLoading:(NSURLConnection *)connection
{
NSString *loginStatus = [[NSString alloc] initWithBytes: [webData mutableBytes] length:[webData length] encoding:NSUTF8StringEncoding];
NSLog(@"%@",loginStatus);
NSString *json_string = [[NSString alloc] initWithData:webData encoding:NSUTF8StringEncoding];
NSDictionary *result = [json_string JSONValue];
NSArray *values = [result objectForKey:@"Result"];
NSMutableArray *results = [[NSMutableArray alloc] init];
for (int index = 0; index<[values count]; index++) {
NSMutableDictionary * value = [values objectAtIndex:index];
Result * result = [[Result alloc] init];
result.UserID = [value objectForKey:@"UserId"];
result.FirstName = [value objectForKey:@"FirstName"];
result.LastName =[value objectForKey:@"LastName"];
result.Email =[value objectForKey:@"Email"];
result.ProfileImage =[value objectForKey:@"ProfileImage"];
result.ThumbnailImage =[value objectForKey:@"ThumbnailImage"];
result.DeviceInfoId =[value objectForKey:@"DeviceInfoId"];
NSLog(@"%@",result.UserID);
[results addObject:result];
[result release];
}
for (int index = 0; index<[results count]; index++) {
Result * result = [results objectAtIndex:index];
//save the object variables to database here
[self createEditableCopyOfDatabaseIfNeeded];
NSString *filePath = [self getWritableDBPath];
sqlite3 *database;
NSTimeInterval timeStamp = [[NSDate date] timeIntervalSince1970];
NSNumber *timeStampObj = [NSNumber numberWithInt: timeStamp];
NSLog(@"%@",timeStampObj);
NSString *journeyid = [NSString stringWithFormat:@"%@_%@_%@", result.UserID, result.DeviceInfoId, timeStampObj];
if(sqlite3_open([filePath UTF8String], &database) == SQLITE_OK) {
const char *sqlStatement = "insert into UserInformation(journeyid,UserID,DeviceId,Username,Password,FirstName,Email) VALUES (?,?,?,?,?,?,?)";
sqlite3_stmt *compiledStatement;
if(sqlite3_prepare_v2(database, sqlStatement, -1, &compiledStatement, NULL) == SQLITE_OK) {
sqlite3_bind_text(compiledStatement, 1, [journeyid UTF8String],-1,SQLITE_TRANSIENT);
sqlite3_bind_text(compiledStatement, 2, [result.UserID UTF8String],-1,SQLITE_TRANSIENT);
sqlite3_bind_text(compiledStatement, 3, [result.DeviceInfoId UTF8String],-1,SQLITE_TRANSIENT);
sqlite3_bind_text(compiledStatement, 4, [txtUserName.text UTF8String],-1,SQLITE_TRANSIENT);
sqlite3_bind_text(compiledStatement, 5, [txtPassword.text UTF8String],-1,SQLITE_TRANSIENT);
sqlite3_bind_text (compiledStatement, 6, [result.FirstName UTF8String],-1,SQLITE_TRANSIENT);
sqlite3_bind_text (compiledStatement, 7, [result.Email UTF8String],-1,SQLITE_TRANSIENT);
}
if(sqlite3_step(compiledStatement) != SQLITE_DONE) {
NSLog(@"Save Error: %s", sqlite3_errmsg(database));
}
else {
UIAlertView *alert = [[UIAlertView alloc]initWithTitle:@"UIAlertView" message:@"Record added" delegate:self cancelButtonTitle:@"OK" otherButtonTitles:nil];
[alert show];
[alert release];
alert = nil;
}
sqlite3_finalize(compiledStatement);
}
sqlite3_close(database);
}
[loginStatus release];
[connection release];
[webData release];
}
的問題是,我想,當用戶輸入他/她的用戶名和密碼,用戶名和密碼應該從服務器數據庫進行驗證,如果用戶是有效的,他應該被允許登錄。請幫我在解決此問題。謝謝
你在這段代碼中面臨什麼問題? – iAmitWagh 2011-06-17 05:56:04
是什麼問題? – 2011-06-17 06:05:56
如果用戶有效或無效,則消息應由服務器在JSON或從JSON創建的字典中返回。如果用戶無效,您能告訴我們服務器返回的內容嗎? – 2011-06-17 06:14:33