協助創建SQL查詢

Question

我正在嘗試創建一個查詢，該查詢只返回一週內有三個或更多訂單的對象，並且僅在9/1/13之後提交訂單。

SELECT OrderID, DateSubmitted, ObjectID = i.ObjectID 
FROM dbo.Object i 
JOIN dbo.Order j 
ON i.ObjectID = j.ObjectID 
WHERE DateSubmitted >= '9/1/2013' 

我只是無法弄清楚如何將結果縮小到一週內有三個或更多訂單的對象。我試過很多GROUP BY和HAVING子句，但沒有運氣。任何幫助將不勝感激。

Answer 1

根據您的最新評論，您查找的查詢非常簡單。使用DatePart函數並找出該對象的訂單日期的WEEK。檢查下面的查詢。除非您的數據庫已默認配置，否則Sunday（int 7）是SQL Server中設置的第一天。所以你爲了這個查詢目的需要設置Monday（int 1）作爲Week的第一天。 你可以通過執行SELECT @@DATEFIRST

檢查當前的設置，如果相同的對象有地方3次以上低於查詢多個星期在返回的每個星期的那個對象。如果只需要對象，則可以從結果集中跳過weekNumber並執行Distinct ObjectID。

不要忘記在結束時將DATEFIRST設置重置爲其原始值。

DECLARE @Object TABLE 
    (
     objectID  INT 
    ) 
    DECLARE @Order TABLE 
    (
     orderID   INT 
     ,objectID  INT 
     ,DateSubmitted DATE  
    ) 

    INSERT INTO @Object(objectID) 
    SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 

    INSERT INTO @Order (orderID, objectID, DateSubmitted) 
       SELECT 1,1,'10/2/2013' 
    UNION ALL SELECT 2,1,'10/3/2013' 
    UNION ALL SELECT 3,1,'10/5/2013' 

    UNION ALL SELECT 4,1,'10/09/2013' 
    UNION ALL SELECT 5,1,'10/10/2013' 
    UNION ALL SELECT 6,1,'10/13/2013' 

    UNION ALL SELECT 4,2,'10/15/2013' 
    UNION ALL SELECT 5,2,'10/16/2013' 
    UNION ALL SELECT 6,2,'10/21/2013' 

    UNION ALL SELECT 7,3,'09/02/2013' 
    UNION ALL SELECT 8,3,'09/03/2013' 
    UNION ALL SELECT 9,3,'09/04/2013' 




    DECLARE @CurrentDateFirst INT=@@DATEFIRST 
    SET DATEFIRST 1; 
    SELECT i.objectID,DATEPART(week,DateSubmitted) AS weekNumber 
    FROM @Object i 
    JOIN @Order j 
    ON i.ObjectID = j.ObjectID 
    WHERE DateSubmitted >= '9/1/2013' 
    GROUP BY i.objectID,DATEPART(week,DateSubmitted) 
    HAVING(COUNT(DISTINCT orderID) >= 3) 
    ORDER BY i.objectID 
    SET DATEFIRST @CurrentDateFirst 

Answer 2

嘗試：

SELECT ObjectID 
FROM dbo.Object i 
JOIN dbo.Order j ON J.ObjectID = i.ObjectID 
WHERE DateSubmitted >= '9/1/2013' 
GROUP BY ObjectID 
HAVING COUNT(1) >=3 

Answer 3

不知道，但我需要在表上 最好的猜測是在SQL

SELECT count(OrderID), i.ObjectID 
FROM dbo.Object i 
JOIN dbo.Order j 
ON i.ObjectID = j.ObjectID 
group by i.ObjectID 
having DateSubmitted >= '9/1/2013' and count(OrderID)>2 

Answer 4

令人費解的詳細信息，但我認爲這會得到你想要的東西.. 。

With WeekSets As 
(
     Select i.ObjectID, 
       j.DateSubmitted, 
       j2.OrderID 
     From dbo.Object i 
     JOIN dbo.Order j 
       ON i.ObjectID = j.ObjectID 
     JOIN dbo.Order j2 
       On j.DateSubmitted <= j2.DateSubmitted 
       And j2.DateSubmitted < DateAdd(Day,7,j.DateSubmitted) 
       And j.ObjectID = j2.ObjectID 
     WHERE j.DateSubmitted >= '9/1/2013' 
),  GroupsOfThree As 
(
     Select ObjectID, 
       DateSubmitted 
     From WeekSets 
     Group By ObjectID, 
        DateSubmitted 
     Having Count(OrderID) >= 3 
) 
Select Distinct j.OrderID, 
     j.DateSubmitted, 
     w.ObjectID 
From GroupsOfThree g 
Join WeekSets w 
     On g.ObjectID = w.ObjectID 
     And g.DateSubmitted = w.DateSubmitted 
Join dbo.Order j 
     On w.ObjectID = j.ObjectID 
     And w.OrderID = j.OrderID