被複制

Question

返回值，我想基於讓所有的重複記錄：

accession_id, 
    check_num, 
    procedure_code, 
    paid_amt, 

此查詢將返回上面的次重複那些字段中的號碼。

但是，我只想返回不止一次出現的那些。

select  
    ACCESSION_PAYMENTS_DAILY_KEY, 
    accession_id, 
    check_num, 
    procedure_code, 
    paid_amt, 
    row_number() 
    over 
    (partition by accession_id, check_num,procedure_code,paid_amt order by ACCESSION_PAYMENTS_DAILY_KEY) as occurrence 
      from  [MILLENNIUM_DW_DEV].[dbo].[F_PAYOR_PAYMENTS_DAILY]   
    where PROCEDURE_CODE is not null 
    and PAID_AMT>0 

當我過濾條件occurrence>1添加到上面的查詢，我收到此錯誤：

Msg 207, Level 16, State 1, Line 13 
Invalid column name 'occurrence'. 

如何僅如果它們發生不止一次，我可以返回記錄？

Answer 1

如果要在WHERE子句中使用別名，則可以將其包裝在另一個SELECT語句中。

SELECT * 
FROM 
(
    select ACCESSION_PAYMENTS_DAILY_KEY, 
    accession_id, 
    check_num, 
    procedure_code, 
    paid_amt, 
    row_number() over (partition by accession_id, check_num,procedure_code,paid_amt order by ACCESSION_PAYMENTS_DAILY_KEY) as occurrence 
    from  [MILLENNIUM_DW_DEV].[dbo].[F_PAYOR_PAYMENTS_DAILY]   
    where PROCEDURE_CODE is not null 
    and PAID_AMT>0 
) x 
WHERE x.occurrence>1 

Answer 2

也許你應該嘗試GROUP BY/HAVING子句：

SELECT accession_id, check_num, procedure_code, paid_amt, 
     COUNT(ACCESSION_PAYMENTS_DAILY_KEY) as occurrences 
FROM [MILLENNIUM_DW_DEV].[dbo].[F_PAYOR_PAYMENTS_DAILY] 
GROUP BY accession_id, check_num, procedure_code,paid_amt 
HAVING COUNT(ACCESSION_PAYMENTS_DAILY_KEY) > 1 

HAVING子句過濾後組記錄由

Answer 3

我已經沒有知道如何你的表建立索引，但是自我離開的加入呢？這可能值得進行測試，但我無法想象它比上述任何一種方法都快。我甚至不會嘗試這一點，除非accession_id和check_num被索引...

Select 
    t1.* 
from [MILLENNIUM_DW_DEV].[dbo].[F_PAYOR_PAYMENTS_DAILY] as t1 
left join [MILLENNIUM_DW_DEV].[dbo].[F_PAYOR_PAYMENTS_DAILY] as t2 
    on t2.accession_id = t1.accession_id 
    and t2.check_num = t1.check_num 
    and t2.procedure_code = t1.procedure_code 
    and t2.paid_amt = t1.paid_amt 
where t2.ACCESSION_PAYMENTS_DAILY_KEY is null 

Answer 4

試試這個：

select accession_id, 
    check_num, 
    procedure_code, 
    paid_amt, 
    COUNT(*) as occurrance 
    from  [MILLENNIUM_DW_DEV].[dbo].[F_PAYOR_PAYMENTS_DAILY]   
    where PROCEDURE_CODE is not null 
    and PAID_AMT>0 
    group by accession_id,check_num,procedure_code,paid_amt 
    having COUNT(*) > 1 

Answer 5

也許替代...

;WITH MoreOne_CTE() 
    AS 
    (
    SELECT  
     ACCESSION_PAYMENTS_DAILY_KEY 
    FROM [MILLENNIUM_DW_DEV].[dbo].[F_PAYOR_PAYMENTS_DAILY]  
    GROUP BY 
      accession_id,  
      check_num, 
      procedure_code, 
      paid_amt 
    HAVING COUNT(*) > 1  
    ) 
SELECT  
     ACCESSION_PAYMENTS_DAILY_KEY ,  
     accession_id,  
     check_num, 
     procedure_code, 
     paid_amt   
FROM [MILLENNIUM_DW_DEV].[dbo].[F_PAYOR_PAYMENTS_DAILY] x 
WHERE 
     PROCEDURE_CODE IS NOT NULL 
     AND PAID_AMT>0 
     AND EXISTS 
      (
        SELECT 1 
        FROM MoreOne_CTE y 
        WHERE x.ACCESSION_PAYMENTS_DAILY_KEY = y.ACCESSION_PAYMENTS_DAILY_KEY 
      )