MATLAB - 屬性

Question

我用matlab創建了一個簡單的密碼程序。如您所知，典型的密碼程序有一個簡單的想法，即如果您錯誤地輸入了三次密碼，程序會向您發送LOCKED！錯誤。 那麼我該如何添加屬性？

while (x ~= 1111) 
    if (x == password) 
     uiwait(msgbox('Welcome!')); 
     break; 
    else 
     uiwait(errordlg('Try Again!!')); 

     X = inputdlg('Please enter your password'); 
     x = str2double (X{1,1}); 
    end 
end 
uiwait(msgbox('Welcome!')); 
end 

Answer 1

你可以把你迭代循環內的計數器：

locked_flag = false 
counter = 0 
while (x ~= 1111) 
    if (x == password) 
     uiwait(msgbox('Welcome!')); 
     break; 
    else 
     uiwait(errordlg('Try Again!!')); 
     counter = counter + 1 
     if (counter == 3) 
      locked_flag = true; 
      %show 'locked' dialog of some kind here 
      break; 
     end 

     X = inputdlg('Please enter your password'); 
     x = str2double (X{1,1}); 
    end 
end 
%can now check if locked_flag true to start unlock logic or other... 

編輯：是的，我只希望你張貼代碼片段，你需要它上面的邏輯，這樣，如果對不起不清楚：

X = inputdlg ('Please enter your password'); 
x = str2double (X {1,1}); 
password = 1111; %whatever 
if (x == password) 
    uiwait(msgbox('Welcome!')); 
else 
    locked_flag = false 
    counter = 1 
    while (x ~= 1111) 
     if (x == password) 
      uiwait(msgbox('Welcome!')); 
      break; 
     else 
      uiwait(errordlg('Try Again!!')); 
      counter = counter + 1 
      if (counter == 3) 
       locked_flag = true; 
       %show 'locked' dialog of some kind here 
       break; 
      end 

      X = inputdlg('Please enter your password'); 
      x = str2double (X{1,1}); 
     end 
    end 
end 
%can now check if locked_flag true to start unlock logic or other... 

Answer 2

wrong = 0; 
lock = false; 

% Keeping a char type allows you to use different 
% types of passwords (i.e. alphanumeric). 
password = '1111'; 

% Infinite loop, which allows you to implement full 
% control over the iterations. 
while (true)  
    pass = inputdlg('Please enter your password:'); 

    % If the user pushes the Cancel button, he is not inserting a 
    % wrong password, so no action should be taken towards locking. 
    % If he pushes the Ok button with empty textbox, {''} is 
    % returned, which could be wrong. 
    if (isempty(pass)) 
     continue; 
    end 

    if (strcmp(pass,password)) 
     uiwait(msgbox('Welcome!')); 
     break; 
    else 
     uiwait(errordlg('Try again!')); 
     wrong = wrong + 1; 

     if (wrong == 3) 
      lock = true; 
      break; 
     end 
    end 
end 

if (lock) 
    uiwait(errordlg('Application locked!')); 
    return; 
end 

% Your logic starts here...