通過標籤迭代

Question

我從

@property (strong, nonatomic) IBOutlet UILabel *lastNumber0; 
@property (strong, nonatomic) IBOutlet UILabel *lastNumber1; 
@property (strong, nonatomic) IBOutlet UILabel *lastNumber2; 
@property (strong, nonatomic) IBOutlet UILabel *lastNumber3; 
@property (strong, nonatomic) IBOutlet UILabel *lastNumber4; 
@property (strong, nonatomic) IBOutlet UILabel *lastNumber5; 
@property (strong, nonatomic) IBOutlet UILabel *lastNumber6; 
@property (strong, nonatomic) IBOutlet UILabel *lastNumber7; 
@property (strong, nonatomic) IBOutlet UILabel *lastNumber8; 
@property (strong, nonatomic) IBOutlet UILabel *lastNumber9; 
@property (strong, nonatomic) IBOutlet UILabel *lastNumber10; 
@property (strong, nonatomic) IBOutlet UILabel *lastNumber11; 
@property (strong, nonatomic) IBOutlet UILabel *lastNumber12; 
@property (strong, nonatomic) IBOutlet UILabel *lastNumber13; 
@property (strong, nonatomic) IBOutlet UILabel *lastNumber14; 
@property (strong, nonatomic) IBOutlet UILabel *lastNumber15; 
@property (strong, nonatomic) IBOutlet UILabel *lastNumber16; 
@property (strong, nonatomic) IBOutlet UILabel *lastNumber17; 
@property (strong, nonatomic) IBOutlet UILabel *lastNumber18; 
@property (strong, nonatomic) IBOutlet UILabel *lastNumber19; 
@property (strong, nonatomic) IBOutlet UILabel *lastNumber20; 
@property (strong, nonatomic) IBOutlet UILabel *lastNumber21; 
@property (strong, nonatomic) IBOutlet UILabel *lastNumber22; 
@property (strong, nonatomic) IBOutlet UILabel *lastNumber23; 

起一堆標籤，而這些都是爲了要通過一個for循環這裏迭代的基礎上通過;

 for (int d = 0; d < [lastNumbers count]; d++) { 
      int value = [[lastNumbers objectAtIndex:d] intValue]; 
      if ([red containsObject:[NSNumber numberWithInteger:value]]) 
      { 
       self.lastNumber0.text = [NSString stringWithFormat:@"%i", value]; 
       self.lastNumber0.textAlignment = NSTextAlignmentLeft; 
       self.lastNumber0.textColor = [UIColor redColor]; 
      } 
      if ([black containsObject:[NSNumber numberWithInteger:value]]) 
      { 
       self.lastNumber0.text = [NSString stringWithFormat:@"%i", value]; 
       self.lastNumber0.textAlignment = NSTextAlignmentRight; 
       self.lastNumber0.textColor = [UIColor blackColor]; 
      } 
      if ([green containsObject:[NSNumber numberWithInteger:value]]) 
      { 
       self.lastNumber0.text = [NSString stringWithFormat:@"%i", value]; 
       self.lastNumber0.textAlignment = NSTextAlignmentCenter; 
       self.lastNumber0.textColor = [UIColor greenColor]; 
      } 
     } 
    } 

希望這是有道理的，在那裏self.lastNumber0.text將與programtical self.lastNumber[d].text <更換 - 我知道這是行不通的，但是這就是我想要實現的，我想這

NSString *labelName = [NSString stringWithFormat:@"lastNumber%i", d]; 

但無法弄清楚該怎麼辦self.labelName.text =嗒嗒......

感謝您的閱讀，如果您需要任何更多的信息只是問。謝謝！

ANSWER

int yInc = 310; 
for (int i = 0; i < 32; i++) { 
    label[i] = [[UILabel alloc] initWithFrame:CGRectMake(460, yInc, 100, 10)]; 
    label[i].font = [UIFont boldSystemFontOfSize:11]; 
    label[i].backgroundColor = [UIColor colorWithRed:0 green:0 blue:0 alpha:0.3]; 
    [self.view addSubview:label[i]]; 
    yInc = yInc - 10; 
} 

      for (int d = 0; d < 32; d++) { 
       int value = [[lastNumbers objectAtIndex:d] intValue]; 
       if ([red containsObject:[NSNumber numberWithInteger:value]]) 
       { 
        label[d].text = [NSString stringWithFormat:@"%i", value]; 
        label[d].textAlignment = NSTextAlignmentLeft; 
        label[d].textColor = [UIColor redColor]; 
       } 
       if ([black containsObject:[NSNumber numberWithInteger:value]]) 
       { 
        label[d].text = [NSString stringWithFormat:@"%i", value]; 
        label[d].textAlignment = NSTextAlignmentRight; 
        label[d].textColor = [UIColor blackColor]; 
       } 
       if ([green containsObject:[NSNumber numberWithInteger:value]]) 
       { 
        label[d].text = [NSString stringWithFormat:@"%i", value]; 
        label[d].textAlignment = NSTextAlignmentCenter; 
        label[d].textColor = [UIColor greenColor]; 
       } 
      } 
     } 

Answer 1

，而不是使一堆IBOutlets的個人標籤，使一個單一的IBOutletCollection到所有的人。現在標籤是數組的元素，您可以循環訪問該數組。