所以即時嘗試創建一個賬戶確認,但它不工作。賬戶確認無法正常工作
這是登錄頁面,它應該檢查帳戶何時被激活,但即使在數據庫中確認該值總是顯示它未被激活,因此它總是顯示未激活的消息。
if(isset($_POST['login_button']))
{
$userName = $_POST['username'];
$userPass = $_POST['password'];
$hashedPass = hash('whirlpool', $userPass);
$query = "SELECT Ime FROM Igraci WHERE Ime = '$userName' AND Lozinka = '$hashedPass'";
$stmt = mysqli_prepare($con, $query) or die(mysqli_error($con));
mysqli_stmt_bind_param($stmt, "ss", $userName, $hashedPass);
mysqli_stmt_execute($stmt);
$result = mysqli_stmt_get_result($stmt);
$row = mysqli_fetch_array($result);
while($conf = mysqli_fetch_assoc(query))
{
$aktiviran = $conf['Confirmed'];
}
if($row)
{
if($aktiviran == 1)
{
$session = md5($userName.$hashedPass);
mysqli_query($con, "UPDATE Igraci SET session = '$session' WHERE Ime = '$userName' AND Lozinka = '$hashedPass'");
setcookie("username", $_POST['username'], time()+3600*24);
setcookie("authorization","ok");
header("Location:welcome.php");
exit();
}
else
{
echo '
<div class="transbox" position = "center">
<center><p>Ovaj racun nije aktiviran, molimo da ga aktivirate.</p>
<p>Ukoliko niste primili email proverite junk folder ili ponovo zatrazite aktivaciju racuna.</p>
</center>
</div>
';
}
}
你用的var_dump得到什麼( $ aktiviran);在if之前? – Tdelang
我得到null,這是什麼意思? 我認爲問題是從數據庫中獲取$ aktiviran,當我把它設置爲像$ aktiviran == 0它確定 – Nathaniel