處理字符串和計數子串的數量beeing看到

Question

如果有一個字符串：

[[some_str,another_str],[some_str,the_str],[some_str,the_str],[some_str,whatever_str]] 

而且我想這樣的輸出：

another_str: 1 
the_str: 2 
whatever_str:1 

我怎麼能這樣做呢？

Answer 1

如果你願意用awk，你可以做這樣的事情：

$ awk -F] -vRS="," '!(NR%2){++a[$1]}END{for(i in a)printf "%s: %s\n",i,a[i]}' <<<"[[some_str,another_str],[some_str,the_str],[some_str,the_str],[some_str,whatever_str]]" 
whatever_str: 1 
another_str: 1 
the_str: 2 

設置字段分隔符]，將記錄分隔到,。計算每秒記錄的發生次數。所有記錄處理完畢後，打印結果。

Answer 2

# read strings into an array, excluding [, ] and , characters 
IFS='[],' read -r -a strings <<<'[[some_str,another_str],[some_str,the_str],[some_str,the_str],[some_str,whatever_str]]' 

# store counts in an associative array 
declare -A counts=() 
for string in "${strings[@]}"; do 
    [[ $string ]] || continue 
    (('counts[$string]' += 1)) 
done 

# iterate over that associative array and print counters 
for string in "${!counts[@]}"; do 
    echo "$string: ${counts[$string]}" 
done