Preg_match_all <a href

Question

Hello i want to extract links <a href="/portal/clients/show/entityId/2121" > and i want a regex which givs me /portal/clients/show/entityId/2121 the number at last 2121 is in other links different any idea?

Answer 1

正則表達式解析鏈接是這樣的：

'/<a\s+(?:[^"'>]+|"[^"]*"|'[^']*')*href=("[^"]+"|'[^']+'|[^<>\s]+)/i' 

既然是多麼的可怕，我會建議使用Simple HTML Dom至少得到鏈接。然後你可以在鏈接href中使用一些非常基本的正則表達式來檢查鏈接。

Answer 2

Paring links from HTML can be done using am HTML parser.

When you have all links, simple get the index of the last forward slash, and you have your number. No regex needed.

Answer 3

Simple PHP HTML Dom Parser例如：

// Create DOM from string 
$html = str_get_html($links); 

//or 
$html = file_get_html('www.example.com'); 

foreach($html->find('a') as $link) { 
    echo $link->href . '<br />'; 
} 

Answer 4

當「解析」HTML我主要依靠PHPQuery：http://code.google.com/p/phpquery/，而不是正則表達式。

Answer 5

Don't use regular expressions for proccessing xml/html。這可以很容易地使用來完成的builtin dom parser：

$doc = new DOMDocument(); 
$doc->loadHTML($htmlAsString); 
$xpath = new DOMXPath($doc); 
$nodeList = $xpath->query('//a/@href'); 
for ($i = 0; $i < $nodeList->length; $i++) { 
    # Xpath query for attributes gives a NodeList containing DOMAttr objects. 
    # http://php.net/manual/en/class.domattr.php 
    echo $nodeList->item($i)->value . "<br/>\n"; 
} 

Answer 6

這是我的解決方案：

<?php 
// get links 
$website = file_get_contents("http://www.example.com"); // download contents of www.example.com 
preg_match_all("<a href=\x22(.+?)\x22>", $website, $matches); // save all links \x22 = " 

// delete redundant parts 
$matches = str_replace("a href=", "", $matches); // remove a href= 
$matches = str_replace("\"", "", $matches); // remove " 

// output all matches 
print_r($matches[1]); 
?> 

我建議避免使用基於XML解析器，因爲你不會總是知道， 文檔是否/網站已經形成良好。

祝你好運