一個字符串

Question

問題Python的檢查列表項是下面的，例如：

lst = ['2456', '1871', '187'] 

d = { 
    '1871': '1', 
    '2456': '0', 
} 

for i in lst: 
    if any(i in x for x in d.keys()): 
     print i 

% python test.py 
2456 
1871 
187 

所以，我需要得到所有這一切都包含在字典的鍵列表「LST」元素「 d「，沒有一個子串匹配，如果我做」打印d [i]「，我得到一個錯誤。

Answer 1

>>> lst = ['2456', '1871', '187'] 
>>> d = { 
    '1871': '1', 
    '2456': '0', 
} 
>>> [x for x in lst if x in d] 
['2456', '1871'] 

Answer 2

使用sets：

lst = ['2456', '1871', '187'] 
d = {'1871': '1', '2456': '0'} 

print(set(lst) & set(d.keys())) # prints '{'2456', '1871'}' 

Answer 3

>>> for i in li: 
    if i in d: 
     print "{0} => {1}".format(i,d[i]) 


2456 => 0 
1871 => 1 

在列表理解：

>>> [i for i in li if i in d] 
['2456', '1871'] 

Answer 4

此行應該做的工作：

l=[e for e in d if e in lst] 

與您的數據：

In [5]: l=[e for e in d if e in lst] 

In [6]: l 
Out[7]: ['2456', '1871']