我很困惑如何序列化和反序列化問題對象列表。序列化對象列表
我有一個調查類有一個屬性稱爲問題,這是一個列表問題對象。
我希望能夠序列化Survey屬性以及每個問題的所有屬性。
不幸的是我到目前爲止沒有運氣,這裏是我的。謝謝您的幫助!
public void loadData(Boolean isSurvey) throws FileNotFoundException {
System.out.println("Select a file: ");
FileInputStream fileIn;
if (isSurvey) {
String fileName = listFiles("surveys").get(input.getIntInput(fileCount - 1));
fileIn = new FileInputStream("surveys/" + fileName);
} else {
String fileName = listFiles("tests").get(input.getIntInput(fileCount - 1));
fileIn = new FileInputStream("tests/" + fileName);
}
Question q = null;
try
{
ObjectInputStream in = new ObjectInputStream(fileIn);
q = (Question) in.readObject();
in.close();
fileIn.close();
}catch(IOException i){
i.printStackTrace();
}catch(ClassNotFoundException c) {
System.out.println("Not found");
c.printStackTrace();
}
System.out.println("Deserialized Question...");
System.out.println("prompt: " + q.prompt);
}
public void saveData(Survey survey, Test test, Boolean isSurvey, String fileName) {
try {
File surveyDir = new File("surveys");
File testDir = new File("tests");
if ((!(surveyDir.exists()) && isSurvey)) {
System.out.println("Creating Survey directory. . .");
surveyDir.mkdir();
}
if ((!(testDir.exists())) && !(isSurvey)) {
System.out.println("Creating Test directory. . .");
testDir.mkdir();
}
if (isSurvey) {
FileOutputStream fileOut = new FileOutputStream("surveys/" + fileName);
ObjectOutputStream out = new ObjectOutputStream(fileOut);
for (Question question : survey.questions) {
out.writeObject(survey.questions);
}
out.close();
fileOut.close();
} else {
FileOutputStream fileOut = new FileOutputStream("tests/" + fileName);
ObjectOutputStream out = new ObjectOutputStream(fileOut);
for (Question question : test.questions) {
out.writeObject(question);
}
out.close();
fileOut.close();
}
} catch(IOException i) {
i.printStackTrace();
}
}
「不走運」是沒有問題的描述。再試一次。 – EJP 2014-10-27 07:11:53
http://stackoverflow.com/questions/26598397/notserializableexception-even-after-implementing-serializable不完整的重複。 – EJP 2014-10-28 00:04:19