計算日期/時間PHP

Question

我需要比較今天的日期。基本上我把它放在2/17/13，它會輸出「昨天」。我試過echo date('l jS F', strtotime('2/15/13'));，但它只會顯示該日期，不會與今天進行比較。

Answer 1

function relativeTime($time) { 

$d[0] = array(1,"second"); 
$d[1] = array(60,"minute"); 
$d[2] = array(3600,"hour"); 
$d[3] = array(86400,"day"); 
$d[4] = array(604800,"week"); 
$d[5] = array(2592000,"month"); 
$d[6] = array(31104000,"year"); 

$w = array(); 

$return = ""; 
$now = time(); 
$diff = ($now-$time); 
$secondsLeft = $diff; 

for($i=6;$i>-1;$i--) 
{ 
    $w[$i] = intval($secondsLeft/$d[$i][0]); 
    $secondsLeft -= ($w[$i]*$d[$i][0]); 
    if($w[$i]!=0) 
    { 
     $return.= abs($w[$i]) . " " . $d[$i][1] . (($w[$i]>1)?'s':'') ." "; 
    } 

} 

$return .= ($diff>0)?"ago":"left"; 
return $return; 
} 

Answer 2

從http://www.highlystructured.com/comparing_dates_php.html

$exp_date = "2006-01-16"; 
$todays_date = date("Y-m-d"); 

$today = strtotime($todays_date); 
$expiration_date = strtotime($exp_date); 

if ($expiration_date > $today) { 
    $valid = "yes"; 
} else { 
    $valid = "no"; 
} 

Answer 3

下面是一個例子，讓你開始：

$when = '2/17/13'; 
$now = new DateTime(); 
// I append $now's time to $then, to make sure we compare 
// the two dates using the same time of the day 
// if you want to compare to $then at 00:00:00, leave it out 
$then = new DateTime($when . ' ' . $now->format('H:i:s')); 

$diff = $now->diff($then); 
switch($diff->days) 
{ 
    case 0: 
     echo 'today'; 
    break; 
    case 1: 
     echo $diff->invert ? 'yesterday' : 'tomorrow'; 
    break; 
    default: 
     echo $diff->invert ? $diff->days . ' days ago' : $diff->days . ' days from now'; 
    break; 
} 

Answer 4

的Drupal附帶了一個非常漂亮的format_interval($interval, $granularity = 2, $langcode = NULL)function。

<?php 
function format_interval($interval, $granularity = 2, $langcode = NULL) { 
    $units = array(
    '1 year|@count years' => 31536000, 
    '1 month|@count months' => 2592000, 
    '1 week|@count weeks' => 604800, 
    '1 day|@count days' => 86400, 
    '1 hour|@count hours' => 3600, 
    '1 min|@count min' => 60, 
    '1 sec|@count sec' => 1, 
); 
    $output = ''; 
    foreach ($units as $key => $value) { 
    $key = explode('|', $key); 
    if ($interval >= $value) { 
     $output .= ($output ? ' ' : '') . format_plural(floor($interval/$value), $key[0], $key[1], array(), array('langcode' => $langcode)); 
     $interval %= $value; 
     $granularity--; 
    } 

    if ($granularity == 0) { 
     break; 
    } 
    } 
    return $output ? $output : t('0 sec', array(), array('langcode' => $langcode)); 
} 
?> 

你不需要運行Drupal來使用它。只需在某處添加上述功能即可。不過，上面的函數還會調用format_plural()--它調用t()（都是自定義的Drupal函數），因此您需要修改上述函數或包含所有這些函數。

你的使用情況：

<?php 
$today = date(); 
$compare = strtotime('2/15/13'); 
$interval = ($today - $compare); 

print format_interval($interval, 1); 
// Outputs '1 day' 
?> 

Answer 5

function checkDate($todaysDate,$expirationDate){ 
$today = strtotime($todays_date); 
$expiration_date = strtotime($exp_date); 

if ($expiration_date > $today) { 
    $valid = "yes"; 
} else { 
    $valid = "no"; 
} 

return $valid 
} 


$expirationDate = "2006-01-16"; 
$todaysDate = date("Y-m-d"); 

$valid=checkDate($todaysDate,$expirationDate) 

做一個函數，那麼你可以用日期的組合使用。然後你可以用一些條件來擴展函數來確定它的「昨天」。