在觸發器中實現條件

因此，我正在使用的環境是MS SQL Server Management Studio，它被證明是觸發器非常痛苦的事情。我想要做的是創建一個觸發器，如果新員工的薪水低於他們分配的部門中的所有其他員工的薪水，則會在新表中插入新員工的信息（SALARY_VIOLATION_NEW_EMP）。在觸發器中實現條件

我有它在哪裏插入新的信息到新表中，我只是無法弄清楚如何實現條件。這是我到目前爲止有：

CREATE TRIGGER SALARY_VIOLATION 
ON EMPLOYEE 
AFTER INSERT 
AS 
BEGIN 

declare @newFname varchar(50), @newLname varchar(50), @newSsn char(9), @newSex char(1), 
     @newSalary decimal(10,2), @newSuper_ssn char(9), @newDno int; 

select @newFname = Fname, 
     @newLname = Lname, 
     @newSsn = Ssn, 
     @newSex = Sex, 
     @newSalary = Salary, 
     @newSuper_ssn = Super_ssn, 
     @newDno = Dno from inserted; 

INSERT INTO SALARY_VIOLATION_NEW_EMP(FirstName,LastName,Ssn,Sex,Salary,Super_ssn,Dno) 
    values(@newFname, @newLname, @newSsn, @newSex, @newSalary, @newSuper_ssn, @newDno); 

END 
GO

爲了節省時間我有滿足兩個表的測試數據：

insert into EMPLOYEE values ('John',null,'doe','234536779',null,null,'M', 20000,'987654321',4)

來源

2014-11-05 bob doe

以供將來參考MySQL是一個不同的數據庫引擎。 – Zane 2014-11-05 21:48:58

你插入的字段中有哪些部門信息是DNO？ – 2014-11-05 21:57:07

與觸發器工作更加有趣，當你不填充變量，而是採取基於集合的方法。

INSERT INTO MyNewTable (ColumnList) 
SELECT ColumnList 
FROM Inserted 
WHERE SomeCondition=true

來源

2014-11-05 21:54:34

如果DNO是你部門人數則：

CREATE TRIGGER SALARY_VIOLATION 
ON EMPLOYEE 
AFTER INSERT 
AS 
BEGIN 

declare @newFname varchar(50), @newLname varchar(50), @newSsn char(9), @newSex char(1), 
    @newSalary decimal(10,2), @newSuper_ssn char(9), @newDno int; 

select @newFname = Fname, 
    @newLname = Lname, 
    @newSsn = Ssn, 
    @newSex = Sex, 
    @newSalary = Salary, 
    @newSuper_ssn = Super_ssn, 
    @newDno = Dno from inserted; 

declare @MinSalary decimal(10,2) 
select @MinSalary = min(Salary) from [EMPLOYEE] where Dno = @newDno and Ssn != @newSsn 

if @MinSalary > @newSalary 
begin 

INSERT INTO SALARY_VIOLATION_NEW_EMP(FirstName,LastName,Ssn,Sex,Salary,Super_ssn,Dno) 
    values(@newFname, @newLname, @newSsn, @newSex, @newSalary, @newSuper_ssn, @newDno); 
end; 

END

來源

2014-11-05 22:00:05

在觸發器中實現條件

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