php從sql數據庫讀取數據

我想學習php，我無法從我的數據庫讀取任何數據！我知道與服務器的連接正在運行，但這條線似乎給我帶來了問題。php從sql數據庫讀取數據

$result = $conn->query($sql);

哪裏$sql = "SELECT firstName, middleName, lastName FROM Base"; 我不知道是什麼問題，但任何提示或答案讚賞。

<!DOCTYPE html> 
<html> 
<head> 
</head> 
<body> 
<h1>My first PHP page</h1> 
<?php 
// connect to database 
$user_name = "superUser"; 
$password = ""; 
$database = "Base"$server = "127.0.0.5"; 
// open connection to the server 
$conn = new mysqli($server, $user_name, $password); 
// echo "Connection to the server is open"; 
// check connetion 
if ($conn->connect_error) { 
    die("Connection failed: " . $conn->connect_error); 
} 
else { 
    print "Connection to the server is open"; 
} 
// load the data from the table 
$sql = "SELECT firstName, middleName, lastName FROM Base"; 
// echo $conn->server_info; 
$result = $conn->query($sql); 
if ($result) { 
    echo "Table was found"; 
} 
else echo "no"; 
/*while($row = $result->fetch_assoc()) { 
echo "id: " . $row["id"]. " - Name: " . $row["firstname"]. " " . $row["lastname"]. "<br />"; 
} 
print $result["firstName"];// ": Number of Rows!" ;*/ 
// if ($result->num_rows > 0) { 
// output data of each row 
// close server connection 
$conn->close(); 
?> 
</body> 
</html>

來源

2015-09-27 James

'mysqli的（$服務器，$ USER_NAME，$密碼，$數據庫）;' –

您沒有選擇你的數據庫。 – aldrin27

以下是mysqli連接示例。

<?php 
$con = mysqli_connect("localhost","my_user","my_password","my_db"); 

// Check connection 
if (mysqli_connect_errno()) 
    { 
    echo "Failed to connect to MySQL: " . mysqli_connect_error(); 
    } 
?>

您忘記了添加數據庫名稱。更改此，

$conn = new mysqli($server, $user_name, $password);

這個

$conn = new mysqli($server, $user_name, $password, $database);

來源

2015-09-27 02:14:45

你先生是GENIUS !!!!非常感謝！！！它總是簡單的事情，讓我們（我）！ – James

不客氣。一旦你掌握了它，PHP很有趣。堅持下去！如果你對這個答案感到滿意，請選擇它作爲正確的:) –

另外，我注意到你的代碼，你有''選擇firstName，middleName，lastName FROM base「'你的數據庫名稱也是」base「是正確的？對於您的選擇查詢，它應該是您要從中檢索的表的名稱，而不是數據庫名稱。例如'「SELECT firstName，middleName，lastName FROM users」;' –

php從sql數據庫讀取數據

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