所以我見過很多例子,並做了大量的Google搜索,並看了堆棧溢出的例子......我需要幫助。我有一個Android應用程序,我在設備上存儲的用戶名和密碼,我需要加密AES他們從256看的例子,這是我到目前爲止有:Android AES 256位加密數據
public class Security {
Cipher ecipher;
Cipher dcipher;
// 8-byte Salt
byte[] salt = {
(byte)0xA9, (byte)0x9B, (byte)0xC8, (byte)0x32,
(byte)0x56, (byte)0x35, (byte)0xE3, (byte)0x03
};
// Iteration count
int iterationCount = 19;
public Security (String passPhrase) {
try {
// Create the key
KeySpec keySpec = new PBEKeySpec(passPhrase.toCharArray(), salt, iterationCount);
SecretKey key = SecretKeyFactory.getInstance(
"PBEWithSHAAndAES").generateSecret(keySpec);
ecipher = Cipher.getInstance(key.getAlgorithm());
dcipher = Cipher.getInstance(key.getAlgorithm());
// Prepare the parameter to the ciphers
AlgorithmParameterSpec paramSpec = new PBEParameterSpec(salt, iterationCount);
// Create the ciphers
ecipher.init(Cipher.ENCRYPT_MODE, key, paramSpec);
dcipher.init(Cipher.DECRYPT_MODE, key, paramSpec);
} catch (Exception e) {
e.printStackTrace();
}
}
public String encrypt(String str) {
try {
// Encode the string into bytes using utf-8
byte[] utf8 = str.getBytes("UTF8");
// Encrypt
byte[] enc = ecipher.doFinal(utf8);
// Encode bytes to base64 to get a string
return Base64.encodeToString(enc, Base64.DEFAULT);
} catch (Exception e) {
e.printStackTrace();
return null;
}
}
public String decrypt(String str) {
try {
// Decode base64 to get bytes
byte[] dec = Base64.decode(str, Base64.DEFAULT);
// Decrypt
byte[] utf8 = dcipher.doFinal(dec);
// Decode using utf-8
return new String(utf8, "UTF8");
} catch (Exception e) {
e.printStackTrace();
return null;
}
}
}
我m試圖使其基於密碼,所以用戶將首次使用用於與服務器通信所需的用戶名和密碼創建一個帳戶,並創建一個PIN作爲存儲在數據庫中的憑證的密鑰。
我主要關心的是這看起來安全嗎?我知道固定鹽是不好的,我該如何解決這個問題?
我知道有許多人喜歡這個一十億的問題,但我希望有人剛出來,並說「這是安全」或「這是不是安全的,改變這一現狀」
謝謝!
編輯:
所以這是我到目前爲止的代碼,它似乎是工作...
public class Security {
Cipher ecipher;
Cipher dcipher;
byte[] salt = new byte[8];
int iterationCount = 200;
public Security(String passPhrase) {
try {
// generate a random salt
SecureRandom random = new SecureRandom();
random.nextBytes(salt);
// Create the key
KeySpec keySpec = new PBEKeySpec(passPhrase.toCharArray(), salt, iterationCount);
SecretKey key = SecretKeyFactory.getInstance(
"PBEWithSHA256And256BitAES-CBC-BC").generateSecret(keySpec);
ecipher = Cipher.getInstance(key.getAlgorithm());
dcipher = Cipher.getInstance(key.getAlgorithm());
// Prepare the parameter to the ciphers
AlgorithmParameterSpec paramSpec = new PBEParameterSpec(salt, iterationCount);
// Create the ciphers
ecipher.init(Cipher.ENCRYPT_MODE, key, paramSpec);
dcipher.init(Cipher.DECRYPT_MODE, key, paramSpec);
} catch (Exception e) {
e.printStackTrace();
}
}
public String encrypt(String str) {
try {
// Encode the string into bytes using utf-8
byte[] utf8 = str.getBytes("UTF8");
// Encrypt
byte[] enc = ecipher.doFinal(utf8);
// Encode bytes to base64 to get a string
return Base64.encodeToString(enc, Base64.DEFAULT);
} catch (Exception e) {
e.printStackTrace();
return null;
}
}
public String decrypt(String str) {
try {
// Decode base64 to get bytes
byte[] dec = Base64.decode(str, Base64.DEFAULT);
// Decrypt
byte[] utf8 = dcipher.doFinal(dec);
// Decode using utf-8
return new String(utf8, "UTF8");
} catch (Exception e) {
e.printStackTrace();
return null;
}
}
public int getIterationCount() {
return iterationCount;
}
public String getSalt() {
return Base64.encodeToString(salt, Base64.DEFAULT);
}
}
我用這個代碼來測試它:
Security s = new Security(pinBox.getText().toString());
String encrypted = s.encrypt(passwordBox.getText().toString());
String decrypted = s.decrypt(encrypted);
builder.setMessage("pin: " + pinBox.getText().toString() + "\n" +
"password: " + passwordBox.getText().toString() + "\n" +
"encrypted: " + encrypted + "\n" +
"decrypted: " + decrypted + "\n" +
"salt: " + s.getSalt());
所以我不需要擔心初始化向量?或者專門硬編碼密碼算法?
再次感謝!
感謝隊友的幫助.. :) – Noman 2013-10-31 11:26:54
你能幫我解決這個問題嗎? http://stackoverflow.com/questions/34061675/convert-ios-encryption-to-android :( – MetaSnarf 2015-12-04 04:07:42