2
我使用pandas
來嘗試計算在兩個日期之間購買了特定類型合同的成員。說我有酷似工作數據框:熊貓根據日期和條件過濾
Member Nbr Contract-Type Date-Joined
20 1 Year Membership 2011-08-01
3128 3 Month Membership 2011-07-22
3535 4 Month Membership 2015-02-18
3760 4 Month Membership 2010-02-28
3762 3 Month Membership 2010-01-31
3882 1 Month Membership 2010-04-24
3892 3 Month Membership 2010-03-24
4116 3 Month Membership 2014-12-02
4700 1 Month Membership 2014-11-11
4802 4 Month Membership 2014-07-26
5004 1 Year Membership 2012-03-12
5020 1 Year Membership 2010-07-28
5022 3 Month Membership 2010-06-25
5130 1 Year Membership 2011-01-04
...
我能夠得到計數如果只有一個合同類型,我很感興趣,使用
print(len(df[(df['Date-Joined'] > '2010-01-01')
& (df['Date-Joined'] < '2012-02-01')
& (df['Member Type'] == '1 Year Membership')]))
當我嘗試類似的東西通過指定1 Year Membership
或4 Month Membership
用下面的代碼
print(len(df[(df['Date-Joined'] > '2013-01-01')
& (df['Date-Joined'] < '2013-02-01')
& (df['Member Type'] == '1 Year Membership')
or (df['Member Type'] == '4 Month Membership')]))
我收到以下錯誤
ValueError: The truth value of a Series is ambiguous. Use a.empty, a.bool(), a.item(), a.any() or a.all().
並通過&
條件更換or
條件返回0
使用'|'而不是'或'。 –
另外,'&'優先於'|,所以你的邏輯可能需要一組括號。 –