2017-06-01 81 views
0

所以我需要插入值到表中,但如果這些值存在,我希望我的腳本不能插入任何東西。我幾乎已經解決了這個問題,但是我的插入語句最終被卡住了。SQL插入如果值不存在

DECLARE @billableitemID int; 
set @billableitemid = (select billableitemID from dbo.treatment where 
@billableitemid=treatment.id) 
set @billableitemID = 256 



CREATE TABLE #MembershipBenefitItem 
    (BenefitID int , 
     BillableItemTypeID int , 
     BillableItemID int 
    ) 

INSERT INTO #MembershipBenefitItem 
    (BenefitID , 
     BillableItemTypeID , 
     BillableItemID 
    ) 

VALUES (23450,1,@billableitemid), 
(57256,1,@billableitemid) 

select m.* from #MembershipBenefitItem AS M 
left join membershipbenefititem AS M1 on m.billableitemid= m1.billableitemid 
and m.billableitemtypeid= m1.billableitemtypeid 
and m.benefitid= m1.benefitID 
and [email protected] and M1.billableitemtypeID=1 and 
M1.benefitID IN(23450,57256) 
where M1.ID is null 

INSERT INTO MembershipBenefitItem 
    (BenefitID, 
     BillableItemTypeID, 
     BillableItemID 
    ) 

select m.BenefitID, m.BillableItemTypeID, m.BillableItemID from 
#MembershipBenefitItem AS M 
left join membershipbenefititem AS M1 on m.billableitemid= m1.billableitemid 
and m.billableitemtypeid= m1.billableitemtypeid 
and m.benefitid= m1.benefitID 
and [email protected] and M1.billableitemtypeID=1 and 
M1.benefitID IN(23450,57256) 
where M1.ID is null 



DROP TABLE #MembershipBenefitItem 
+0

另一種方式做這樣的事情會在合併聲明。只是一個想法。通常雖然這用於如果存在更新其他插入 –

+0

你卡在什麼? –

+1

'Where ...並且不存在(鍵上的相關子查詢)' – xQbert

回答

1

這看起來像使用Merge語句的好例子。

https://docs.microsoft.com/en-us/sql/t-sql/statements/merge-transact-sql

它看起來是這樣的:

MERGE MembershipBenefitItem AS trg 
USING #MembershipBenefitItem AS src 
ON src.BillableItemID = trg.BillableItemID --and other join conditions 
WHEN NOT MATCHED BY TARGET THEN 
INSERT (col1, col2, col3) -- this will be inserted into trg table 
VALUES (src.val1, src.val2, src.val3)