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我試圖用Ajax更改div的內容,但沒有任何反應......有人能幫我看看我做錯了什麼嗎?AJAX更改HTML內容
據我所見我沒有遺漏任何東西,但按鈕不能連接。我正在運行XAMPP並打開了apache。
索引頁
<!DOCTYPE html>
<html>
<head>
<title></title>
<meta name="author" content="Malecia Legodi">
<meta name="description" content="Reload Website">
<script language="JavaScript" src="javascript.js"></script>
</head>
<body style="background-color:green">
<div>
<nav>
<table>
<tr>
<td>
<input type="button" id="home" value="Home"/>
</td>
<td>
<input type="button" id="contact" value="contact" />
</td>
</table>
</nav>
<section>
<div id="content" >
<h1>Content Review Summary</h1>
<p>
aaa...
</p>
<p>
bbb...
</p>
</div>
</section>
<footer align="center">© Reload Website</footer>
</div>
</body>
</html>
接觸頁:
<h1>Content Review Summary</h1>
<p>
ccc...
</p>
<p>
ddd...
</p>
Javascript.js
function initiate(){
content = document.getElementById('content');
var home = document.getElementById('home');
var contact = document.getElementById('contact');
home.addEventListener('click', readHome, false);
contact.addEventListener('click', readContact, false);
}
function readHome(){
var url = "home.html";
var request = new XMLHttpRequest();
request.addEventListener('load', showContent, false);
request.open("GET", url, true);
request.send();
}
function readContact(){
var url = "contact.html";
var request = new XMLHttpRequest();
request.addEventListener('load', showContent, false);
request.open("GET", url, true);
request.send();
}
//function showContent() to add data into your
function showContent(e){
//add data to secContent
content.innerHTML = e.target.responseText;
}
//use the listener to load your initiate() function
window.addEventListener('load', initiate, false);
您是否收到任何錯誤? – ankur 2014-11-03 06:31:29
你在哪裏聲明瞭內容變量? – Amy 2014-11-03 06:33:38
@ankur,不,我沒有得到任何錯誤,頁面根本不會改變。 – 2014-11-03 06:37:53