我目前正在嘗試創建一個班級時間表,我從我的Sql Server數據庫中使用PHP進行抽取,並且試圖獲取佈局輸出以及數據,因爲我正在分組資源。foreach()循環輸出數據和創建佈局
這些分組嵌套如:
-DAY
--TIME
---CLASS
----STUDENTS
我的電流輸出工作,但,它只在第一個循環中,然後一切都變得不合時宜。我假設我的代碼中有一個錯誤的</div>
標記,但我無法爲我的生活找到它。
我的PHP代碼是一個函數,delcare這樣:
<div class="mainScheduleWrapper">
<?php daySchedule(); ?>
</div>
我的PHP代碼是這樣的:
function daySchedule() {
global $conn;
$dayScheduleQuery = 'SET DATEFIRST 1
SELECT [DAY].[DAY] AS [DAY], CLASS.CLASSTIME AS CLASSTIME, CLASSLEVEL.CLASSLEVEL AS CLASSLEVEL, CLASS.MAXSTUDENT AS MAXSTUDENT, INSTRUCTOR.FIRSTNAME AS INSTRUCTOR, STUDENT.FIRSTNAME AS STUDENTFIRST, STUDENT.SURNAME AS STUDENTLAST, STUDENT.DOB AS STUDENTDOB
FROM STUDENT JOIN BOOKING ON STUDENT.ID = BOOKING.STUDENTID JOIN CLASS ON CLASS.ID = BOOKING.CLASSID JOIN CLASSLEVEL ON CLASS.CLASSLEVELID = CLASSLEVEL.ID JOIN [DAY] ON CLASS.CLASSDAY = [DAY].ID JOIN INSTRUCTOR ON CLASS.INSTRUCTORID = INSTRUCTOR.ID
WHERE [DAY].ID = (DATEPART(dw, GETUTCDATE() AT TIME ZONE \'AUS Eastern Standard Time\'))
ORDER BY CLASS.CLASSTIME ASC, INSTRUCTOR.FIRSTNAME ASC, CLASSLEVEL.CLASSLEVEL ASC';
// COUNTERS
$t = 0;
$i = 0;
//VARIABLES FOR DAY SCHEDULE
$classDay = NULL;
$classTime = NULL;
$classInstructor = NULL;
$closeClass = false;
$closeAll = false;
$queryConnector = $conn->query($dayScheduleQuery);
foreach ($queryConnector as $schedule) {
// CLASS DAY HEADER
if ($classDay != $schedule['DAY']) {
echo '<div class="grid-1">';
echo '<h1>' . $schedule['DAY'] . '</h1>';
echo '</div><!-- Day closed! -->';
$classDay = $schedule['DAY'];
}
// CLASS TIME HEADER
if ($classTime != $schedule['CLASSTIME']) {
if($classTime != $schedule['CLASSTIME'] && $t > 0) {
$closeAll = true;
goto closeAll;
}
echo '<div class="grid-12-noGutter scheduleContainer">'; //NON-CLOSED
echo '<h1>' . 'T = ' . $t . '</h1>';
echo '<div class="grid-middle-center col scheduleTimeTab">';
// FIX 3 DIGIT MILITARY TIME
if (strlen($schedule['CLASSTIME']) < 4) {
$classScheduleTime = '0' . $schedule['CLASSTIME'];
} else {
$classScheduleTime = $schedule['CLASSTIME'];
}
echo '<p>' . date('g:i A', strtotime($classScheduleTime)) . '</p>';
echo '</div>'; //CLOSE TIME TAB
echo '<div class="innerSchedule">'; // NON-CLOSED
$classTime = $schedule['CLASSTIME'];
$t += 100;
}
// INSTRUCTOR HEADER
if ($classInstructor != $schedule['INSTRUCTOR']) {
if ($classInstructor != $schedule['INSTRUCTOR'] && $i > 0) {
$closeClass = true;
goto closeClassWrapper;
}
echo '<div class="classWrapper">';
echo '<h1>' . 'I =' . $i . 'T = ' . $t . '</h1>';
echo '<div class="grid-3-middle classHeader">';
echo '<div class="col classHeaderCell' . classLevelColour($schedule['CLASSLEVEL']) . '">' . $schedule['CLASSLEVEL'] . '</div>';
echo '<div class="col classHeaderCell">' . $schedule['INSTRUCTOR'] . '</div>';
echo '<div class="col classHeaderCell">Max' . ' ' . $schedule['MAXSTUDENT'] . '</div>';
echo '</div>';
echo '<div class="grid-4-middle" id="studentHeaders">';
echo '<div class="col"><h6>Student Name</h6></div>';
echo '<div class="col"><h6>Student Birthday</h6></div>';
echo '<div class="col"><h6>Class Level</h6></div>';
echo '<div class="col"><h6>Attendance</h6></div>';
echo '</div>';
$classInstructor = $schedule['INSTRUCTOR'];
$i += 100;
}
echo '<div class="grid-4 studentRow">';
echo '<div class="col">';
echo '<span class="studentCell">' . $schedule['STUDENTFIRST'] . ' ' . $schedule['STUDENTLAST'] . '</span>';
echo '</div>';
echo '<div class="col">';
echo '<span class="studentCell">' . $schedule['STUDENTDOB'] . '</span>';
echo '</div>';
echo '<div class="col">';
echo '<span class="studentCell">' . $schedule['CLASSLEVEL'] . '</span>';
echo '</div>';
echo '<div class="col">';
echo '<span class="studentCell">--</span>';
echo '</div>';
echo '</div>';
// GOTO TAGS
closeClassWrapper: {
if ($closeClass === true) {
echo '</div>';
$closeClass = false;
$i = 0;
}
}
closeAll: {
if ($closeAll === true) {
echo '</div>';
echo '</div>';
echo '</div>';
$closeAll = false;
$t = 0;
$i = 0;
}
}
}
}
任何幫助將不勝感激 - 即使它是來告訴我我會以完全錯誤的方式去解決這個問題。
最親切的問候 邁克爾ž
你爲什麼用PHP構建你的佈局,這個壞主意 – meda
你能給我一些關於如何以任何其他方式從一個數據庫(總是正在更新)構建這個結構的建議嗎? – user3436334
當然,你需要分離關注點,你的視圖應該只是一個'HTML'文件,然後用'javascript'('AJAX')向你的服務器發出請求,你應該只使用PHP來執行查詢並返回'JSON數據返回給你的客戶。 – meda