的關聯數組的每個詞的出現次數,讓所述陣列是作爲PHP:計數在字符串
{
element [0] = 'Mary',
element [1] = 'Mary had a little',
element [2] = 'a lamb',
element [3] = 'Mary mary mary',
.
.
element [n] = 'lady'
}
輸出:
Mary : 5
a : 2
had : 1
little : 1
lady : 1
的關聯數組的每個詞的出現次數,讓所述陣列是作爲PHP:計數在字符串
{
element [0] = 'Mary',
element [1] = 'Mary had a little',
element [2] = 'a lamb',
element [3] = 'Mary mary mary',
.
.
element [n] = 'lady'
}
輸出:
Mary : 5
a : 2
had : 1
little : 1
lady : 1
<?php
$array=array(
0 => 'Mary',
1 => 'Mary had a little',
2 => 'a lamb',
3 => 'Mary mary mary',
4 => 'lady'
);
$data=array();
foreach($array as $sentence)
{
//gatering words in an array by spliting the sentence on space.
$data= array_merge($data,explode(" ", $sentence));
}
//counting values present in array for case sensitive
$result=array_count_values($data);
print_r($result); //Result 1
//counting values present in array for case insensitive by changing each array element to lowercase
$result=array_count_values(array_map("strtolower", $data));
print_r($result); //Result 2
輸出:
//result 1
Array
(
[Mary] => 3
[had] => 1
[a] => 2
[little] => 1
[lamb] => 1
[mary] => 2
[lady] => 1
)
//result 2
Array
(
[mary] => 5
[had] => 1
[a] => 2
[little] => 1
[lamb] => 1
[lady] => 1
)
儘管這段代碼可以解決這個問題,但[包括解釋](http://meta.stackexchange.com/questions/114762/explaining-entirely-code-based-answers)確實有助於提高您的帖子的質量。請記住,您將來會爲讀者回答問題,而這些人可能不知道您的代碼建議的原因。也請儘量不要用解釋性註釋來擠佔代碼,這會降低代碼和解釋的可讀性! – Rizier123
@Rizier加解釋 –
你可能每個字存儲到與一個正則表達式的數組,然後使用http://php.net/manual/en/function.array-count-values.php計數唯一身份......或者你可以迭代並在空間上爆炸。 – chris85
請顯示您迄今嘗試過的內容 –
$ result = mysqli_query($ connection,$ query4); $ json = mysqli_fetch_all($ result,MYSQLI_ASSOC); echo json_encode($ json); – Lubi