0
我有如下這個DTD此XML文件:http://www.edrdg.org/jmdict/jmdict_dtd_h.html反序列化XML文件XmlSerializer的,但一個屬性包含其名稱中的冒號
你可以看到,2個元素包含的屬性在他們的名字一個冒號(:
) :
L源和光澤可以包含命名xml:lang
一個屬性,因爲在這個例子中看到(用於L源元素):
<entry>
<ent_seq>1002480</ent_seq>
<k_ele>
<keb>お転婆</keb>
</k_ele>
<k_ele>
<keb>御転婆</keb>
</k_ele>
<r_ele>
<reb>おてんば</reb>
</r_ele>
<sense>
<pos>&adj-na;</pos>
<pos>&n;</pos>
<misc>&uk;</misc>
<lsource xml:lang="dut">ontembaar</lsource>
<gloss>tomboy</gloss>
</sense>
</entry>
我不如何確保定義我的課代表lsource
元素,在這裏它是現在,但它缺少這個屬性:
[System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "4.7.2046.0")]
[System.SerializableAttribute()]
[System.Diagnostics.DebuggerStepThroughAttribute()]
[System.ComponentModel.DesignerCategoryAttribute("code")]
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true, Namespace = "JMdict_e.dtd")]
[System.Xml.Serialization.XmlRootAttribute(Namespace = "JMdict_e.dtd", IsNullable = false)]
public partial class lsource
{
private string ls_typeField;
private string ls_waseiField;
private string valueField;
/// <remarks/>
[System.Xml.Serialization.XmlAttributeAttribute()]
public string ls_type
{
get
{
return this.ls_typeField;
}
set
{
this.ls_typeField = value;
}
}
/// <remarks/>
[System.Xml.Serialization.XmlAttributeAttribute()]
public string ls_wasei
{
get
{
return this.ls_waseiField;
}
set
{
this.ls_waseiField = value;
}
}
/// <remarks/>
[System.Xml.Serialization.XmlTextAttribute()]
public string Value
{
get
{
return this.valueField;
}
set
{
this.valueField = value;
}
}
}
我應該如何命名屬性XmlSerializer的正確識別和解析屬性?我嘗試添加屬性public string xml_lang { get; set; }
或public string lang { get; set; }
但都未能從XML文件解析屬性時XmlSerializer.Deserialize被稱爲