簡單的SQL查詢

Question

我有一個SQL查詢的問題。假設我們有：

cinema 
    name 
    id_cinema 
    cinema 
    city 

movies 
    id_movie 
    name_movie 

假設：

• 電影可以在更多的影院中可以看出;
• 在電影院裏你可以看到不同的電影;

我有一個類型的表之間的關係：多對多。因此，其具有主鍵id_cinemaid_film表cinema-movie我需要。

是否有一個SQL查詢，讓我在電影院所有的電影？

Answer 1

查詢將

select m.* from movies m left join cinema_movie mc on m.id = mc.movie_id where mc.cinema_id = 1; 

E.g.

mysql> select * from movies; 
+------+--------+ 
| id | name | 
+------+--------+ 
| 1 | movie1 | 
| 2 | movie2 | 
| 3 | movie3 | 
| 4 | movie4 | 
+------+--------+ 
4 rows in set (0.00 sec) 

mysql> select * from cinema; 
+------+-------+---------+ 
| id | name | cinema | 
+------+-------+---------+ 
| 1 | name1 | cinema1 | 
| 2 | name2 | cinema2 | 
| 3 | name3 | cinema3 | 
| 4 | name4 | cinema4 | 
+------+-------+---------+ 
4 rows in set (0.00 sec) 

mysql> select * from cinema_movie; 
+----------+-----------+ 
| movie_id | cinema_id | 
+----------+-----------+ 
|  1 |   1 | 
|  3 |   1 | 
|  4 |   1 | 
|  1 |   3 | 
|  3 |   3 | 
+----------+-----------+ 
5 rows in set (0.00 sec) 

mysql> select m.* from movies m left join cinema_movie mc on m.id = mc.movie_id where mc.cinema_id = 1; 
+------+--------+ 
| id | name | 
+------+--------+ 
| 1 | movie1 | 
| 3 | movie3 | 
| 4 | movie4 | 
+------+--------+ 
3 rows in set (0.00 sec) 

Answer 2

顯示從電影院10的所有電影：

SELECT movies.* 
FROM movies 
JOIN cinema_movie ON cinema_movie.id_film = movies.id_movie 
WHERE cinema_movie.id_cinema = 10 

隨着JOIN這樣的（內部連接），你可以從movies選擇並加入cinema_movie，反之亦然 - 順序並不重要。

Answer 3

查詢與電影信息：

select * from movies as m 
join cinema_movie as cm 
on m.id_movie = cm.id_movie 
join cinema as c 
on c.id_cinema = cm.id_cinema 
where c.id_cinema = <your id_cinema> 

Answer 4

如果您有：

cinema 
    name 
    id_cinema 
    cinema 
    city 

movies 
    id_movie 
    name_movie 

cinema_movie 
    id_cinema 
    id_movie 
    start_time 

然後你就可以參加由：

SELECT cinema_movies.id_cinema, name, cinema, cinema_movies.id_movie, name_movie 
FROM cinema, movies, cinema_movies 
WHERE cinema.id_cinema = cinema_movies.id_cinema 
    AND movies.id_movie = cinema_movies.id_movie 
    AND cinema_movies.id_cinema = 'northpark12' 

Answer 5

如果您想通過cinema.name到SEACH：

SELECT cinema.name 
    , movies.* 
FROM movies 
    INNER JOIN cinema_movie 
    ON cinema_movie.id_film = movies.id_movie 
    INNER JOIN cinema 
    ON cinema_movie.id_cinema = cinema.id_cinema 
WHERE cinema.name = "YourCinemaName" 

如果你想通過id_cinema搜索：如果您想搜索特定cinema.id

SELECT cinema.name 
    , movies.* 
FROM movies 
    INNER JOIN cinema_movie 
    ON cinema_movie.id_film = movies.id_movie 
    INNER JOIN cinema 
    ON cinema_movie.id_cinema = cinema.id_cinema 
WHERE cinema.id_cinema = YourCinemaID 

和你不想輸出電影的名字，Box9的答案就夠了。