2017-08-17 352 views
-1

我是PHP,HTML5和CSS的全新軟件。我正在建立我的網站。地址是This。當我點擊開始免費試用它意味着將用戶註冊到數據庫並讓他們訪問網站上的其他頁面。然後他們登錄。問題是,當點擊開始免費試用時,用戶可以訪問其他頁面,但我無法通過Cpanel中的phpMyAdmin在數據庫字段/列中看到註冊。據我所知server.php(下面)連接到數據庫服務器,這就是爲什麼訪問被授予其他網頁。註冊和登錄系統

嘗試登錄時,框架內會顯示錯誤對話框。下面的代碼應該工作嗎?還是有什麼我做錯了?希望我已正確發佈我的server.php

<?php 
session_start(); 

// variable declaration 
$fname = ""; 
$lname = ""; 
$username = ""; 
$email = ""; 
$password = ""; 
$errors = array(); 
$_SESSION['success'] = ""; 

$dbh = mysqli_connect ("localhost", "usrname", "password") 
or die ('I cannot connect to the database.'); 
mysqli_select_db ("db_name"); 




// REGISTER USER 
if (isset($_POST['reg_user'])) { 
    // receive all input values from the form 
    $fname = mysqli_real_escape_string($dbh, $_POST['fname']); 
    $lname = mysqli_real_escape_string($dbh, $_POST['lname']); 
    $username = mysqli_real_escape_string($dbh, $_POST['username']); 
    $email = mysqli_real_escape_string($dbh, $_POST['email']); 
    $password_1 = mysqli_real_escape_string($dbh, $_POST['password_1']); 
    $password_2 = mysqli_real_escape_string($dbh, $_POST['password_2']); 

    // form validation: ensure that the form is correctly filled 
    if (empty($fname)) { array_push($errors, "First Name is required"); } 
    if (empty($lname)) { array_push($errors, "Last Name is required"); } 
    if (empty($username)) { array_push($errors, "Username is required"); } 
    if (empty($email)) { array_push($errors, "Email is required"); } 
    if (empty($password_1)) { array_push($errors, "Password is required"); } 

    if ($password_1 != $password_2) { 
     array_push($errors, "The two passwords do not match"); 
    } 

    // register user if there are no errors in the form 
    if (count($errors) == 0) { 
     $password = md5($password_1);//encrypt the password before saving in the database 
     $query = "INSERT INTO users (fname, lname, username, email, password) 
        VALUES('$fname','$lname', '$username', '$email', '$password')"; 
     mysqli_query($dbh, $query); 

     $_SESSION['username'] = $username; 
     $_SESSION['success'] = "You are now logged in"; 
     header('location: Continue.php'); 
    } 

} 

// ... 

// LOGIN USER 
if (isset($_POST['login_user'])) { 
    $username = mysqli_real_escape_string($dbh, $_POST['username']); 
    $password = mysqli_real_escape_string($dbh, $_POST['password']); 

    if (empty($username)) { 
     array_push($errors, "Username is required"); 
    } 
    if (empty($password)) { 
     array_push($errors, "Password is required"); 
    } 

    if (count($errors) == 0) { 
     $password = md5($password); 
     $query = "SELECT * FROM users WHERE username='$username' AND password='$password'"; 
     $results = mysqli_query($dbh, $query); 

     if (mysqli_num_rows($results) == 1) { 
      $_SESSION['username'] = $username; 
      $_SESSION['success'] = "You are now logged in"; 
      header('location: Continue.php'); 
     }else { 
      array_push($errors, "Wrong username/password combination"); 
     } 
    } 
} 
+0

聽起來像是你的SQL查詢失敗。試着在SQL之後立即殺死你的腳本,看看用mysqli_error($ dbh)拋出了什麼錯誤。' – IsThisJavascript

+0

WillParky93謝謝你。會放棄一下。 –

+0

'mysqli_select_db(「db_name」);'失敗了。閱讀該手冊,您將看到它的語法。 –

回答

0

感謝WillParky93和Fred -ii指出我正確的方向。這已經解決了通過更改此

$dbh = mysqli_connect ("localhost", "usrname", "password") 
or die ('I cannot connect to the database.'); 
mysqli_select_db ("db_name"); 

$dbh = mysqli_connect ("localhost", "usrname", "password") 
or die ('I cannot connect to the database.'); 
mysqli_select_db ($dbh, "db_name");