蟒蛇 - 沒有輸出也沒有錯誤信息

Question

import requests 
from bs4 import BeautifulSoup 

url = "https://twitter.com/realDonaldTrump?ref_src=twsrc%5Egoogle%7Ctwcamp%5Eserp%7Ctwgr%5Eauthor" 

r = requests.get(url) 

soup = BeautifulSoup(r.content, "html.parser") 

links = soup.find_all("a") 

g_data = soup.find_all("div", {"class": "content"}) 

n_data = soup.find_all("strong", {"class": "fullname show-popup-with-id "}) 

c_data = soup.find_all("p", {"class": "TweetTextSize TweetTextSize--normal js-tweet-text tweet-text"}) 

for item in g_data: 

    try: 

     print(item.contents[0].find_all(n_data)[0].text) 

    except: 

     pass 

當我試着運行上面的代碼，沒有顯示錯誤信息。唯一顯示的是runfile（myfilepath），wdir（另一個路徑）。我期待輸出的名字在本例中是「唐納德特朗普」。任何幫助或建議？我使用spyder（python 3.6）作爲我的平臺。

Answer 1

你print(item.contents[0].find_all(n_data)[0].text)應該是print(item.find_all("strong", {"class": "fullname show-popup-with-id "})[0].text)

import requests 
from bs4 import BeautifulSoup 

url = "https://twitter.com/realDonaldTrump?ref_src=twsrc%5Egoogle%7Ctwcamp%5Eserp%7Ctwgr%5Eauthor" 

r = requests.get(url) 
soup = BeautifulSoup(r.content, "html.parser") 

links = soup.find_all("a") 
g_data = soup.find_all("div", {"class": "content"}) 
n_data = soup.find_all("strong", {"class": "fullname show-popup-with-id "}) 
c_data = soup.find_all("p", {"class": "TweetTextSize TweetTextSize--normal js-tweet-text tweet-text"}) 

for item in g_data: 
    try: 
     print(item.find_all("strong", {"class": "fullname show-popup-with-id "})[0].text) # chain the n_data here 
    except: 
     pass 

輸出將是

Donald J. Trump ... ... ... Donald J. Trump

Answer 2

代碼

except: 

     pass 

的這部分有效地抑制錯誤消息。