2010-05-07 241 views
0

比方說,我有對象的同一類的數組,關切的兩個屬性在這裏:名稱和created_at。刪除「重複對象」

如何找到數組中的同名(DUP的考慮)的對象,然後刪除數據庫中的重複記錄。但是,具有最新的created_at日期的對象是必須刪除的對象。

回答

2
seen = [] 
#sort by created date and iterate 
collection.sort({|a,b| a.created_at <=> b.created_at}).each do |obj| 
    if seen.map(&:name).include? obj.name #check if the name has been seen already 
    obj.destroy! 
    else 
    seen << obj #if not, add it to the seen array 
    end 
end 

應該有希望完成這項工作。

+0

有語法錯誤,在這裏,但我得到它的工作。謝謝! – keruilin 2010-05-07 17:10:49

+0

哦,對不起,錯過了那個,現在應該修好。 – 2010-05-07 17:30:08

+0

做'seen = Set.new'會更好。那樣'include?'是O(1)而不是O(n)。 – 2012-09-15 17:31:15

0

如果這僅僅是在桌子上引入UNIQUE INDEX前一次修正錯誤,你不妨做在SQL:

DELETE FROM t WHERE id IN (
    SELECT t1.id 
    FROM t t1 
    LEFT JOIN t t2 ON t1.name = t2.name AND t2.created_at < t1.created_at 
    WHERE t2.id IS NOT NULL 
)