我使用的是php和CodeIgniter。我在這兩個(職業生涯VB.Net和C#開發人員)的新手。然而,試圖創建一個基本的註冊表單,我很難讓jQuery驗證工作。無法讓jQuery驗證工作
的header.php
<?php defined('BASEPATH') OR exit('No direct script access allowed'); ?><!DOCTYPE html>
<html>
<head>
<?php if(isset($title)) {?>
<title>Discuss Cards - <?php echo $title ?></title>
<?php } else { ?>
<title>Discuss Cards</title>
<?php } ?>
<link rel="stylesheet" href="<?php echo base_url();?>styles/forum.css" type="text/css"><script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.0/jquery.min.js"> </script>
<script src="<?php echo base_url();?>js/jquery.validate.min.js"></script>
</head>
<body>
<?php if(isset($title)) {?>
<h1><?php echo $title?></h1>
<?php } ?>
<?php if (isset($page_description)) {?>
<p id="page_description"><?php echo $page_description?></p>
<?php } ?>
create.php
<script>
$("#createaccount").validate();
</script>
<?php $attributes = array('id'=>'createaccount');
echo form_open('user/create_account',$attributes); ?>
<?php echo form_label('Email','txtEmail');?>
<br />
<?php $data = array('type'=>'email','name'=>'txtEmail','id'=>'txtEmail','maxlength'=>'50','minlength'=>'2');
echo form_input($data); ?>
<br /><br />
<?php echo form_label('Username','txtUsername');?>
<br />
<?php $data = array('name'=>'txtUsername','id'=>'txtUsername','maxlength'=>'50','minlength'=>'5');
echo form_input($data); ?>
<br /><br />
<?php echo form_label('Password','pswPassword');?>
<br />
<?php $data = array('name'=>'pswPassword','id'=>'pswPassword');
echo form_password($data); ?>
<br /><br />
<?php echo form_label('Confirm Password','pswConfirmPassword');?>
<br />
<?php $data = array('name'=>'pswConfirmPassword','id'=>'pswConfirmPassword');
echo form_password($data); ?>
<br /><br />
<input type="submit" value="Register" name="Register" />
<?php echo form_close();?>
footer.php
<strong>© 2016</strong>
</body>
</html>
結果...
<!DOCTYPE html>
<html>
<head>
<title>Discuss Cards - Create New Account</title>
<link rel="stylesheet" href="http://[::1]/forum/styles/forum.css" type="text/css">
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.0/jquery.min.js"></script>
<script src="http://[::1]/forum/js/jquery.validate.min.js"></script>
</head>
<body>
<h1>Create New Account</h1>
<script>
$("#createaccount").validate();
</script>
<form action="http://[::1]/forum/index.php/user/create_account" id="createaccount" method="post" accept-charset="utf-8">
<label for="txtEmail">Email</label>
<br>
<input type="email" name="txtEmail" value id="txtEmail" maxlength="50" minlength="2">
<br>
<br>
<label for="txtUsername"></label>
<br>
<input type="text" name="txtUsername" value id="txtUsername" maxlength="50" minlength="5">
<br>
<br>
<label for="pswPassword">Password</label>
<br>
<input type="password" name="pswPassword" value id="pswPassword">
<br>
<br>
<label for="pswConfirmPassword">Confirm Password</label>
<br>
<input type="password" name="pswConfirmPassword" value id="pswConfirmPassword">
<br>
<br>
<input type="submit" value="Register" name="Register">
</form>
<strong>© 2016</strong>
</body>
</html>
現在,指向js和css文件的鏈接是正確的。我使用的例子從http://jqueryvalidation.org/documentation/:
<form class="cmxform" id="commentForm" method="get" action="">
<fieldset>
<legend>Please provide your name, email address (won't be published) and a comment</legend>
<p>
<label for="cname">Name (required, at least 2 characters)</label>
<input id="cname" name="name" minlength="2" type="text" required>
</p>
<p>
<label for="cemail">E-Mail (required)</label>
<input id="cemail" type="email" name="email" required>
</p>
<p>
<label for="curl">URL (optional)</label>
<input id="curl" type="url" name="url">
</p>
<p>
<label for="ccomment">Your comment (required)</label>
<textarea id="ccomment" name="comment" required></textarea>
</p>
<p>
<input class="submit" type="submit" value="Submit">
</p>
</fieldset>
</form>
<script>
$("#commentForm").validate();
</script>
不過,我覺得我失去了一些東西,因爲它不工作。當我使用他們的演示(http://jqueryvalidation.org/files/demo/)時,會在顯示錯誤的輸入區域下創建一個新標籤。但是,當我測試我的代碼時(Notepadd ++,Google Chrome的最新版本,WAMPServer 2.5),我只能獲得Chrome驗證。有人能告訴我我做錯了什麼嗎?謝謝。
這樣做。真心感謝您的幫助。 – XstreamINsanity
@XstreamINsanity它幫了大忙!你是最受歡迎的。 – Zimmi