-5
我正在構建一個儀表板,其中的數據是從數據庫動態收集的。用於獲取數據的文件在php中,並且正在使用ajax請求進行調用。但是當我運行腳本時,出現錯誤500,內部服務器錯誤。加載php腳本時出錯500內部服務器錯誤
我一直在尋找一個解決方案几天,但還沒有找到任何解決方案。
也許我在代碼中忽略了一些東西?
include('db/mysqli_con.php');
// check if the selected year and the user key have been sent
if(!empty($_POST["selectYear"]) && !empty($_POST["token"])){
// Define selected year, start date and end date variables for query
$year = $_POST["selectYear"];
$startDate = new DateTime("".$year."-01-01");
$endDate = new DateTime("".$year."-12-31");
$token = $_POST["token"];
$output = '';
// For every day between start date and end date, define variable $day
for($day = $begin; $day <= $end; $day->modify('+1 day')) {
// save date as a string
$dayString = $day->format("Y-m-d");
$newDate = "".$dayString." 00:00:00";
list($y, $m, $d) = explode("-", $dayString);
// avoid octal values in output
if($m == 01) {
$newm = 1;
}elseif($m == 02) {
$newm = 2;
}elseif($m == 03) {
$newm = 3;
}elseif($m == 04) {
$newm = 4;
}elseif($m == 05) {
$newm = 5;
}elseif($m == 06) {
$newm = 6;
}elseif($m == 07) {
$newm = 7;
}elseif($m == 08) {
$newm = 8;
}elseif($m == 09) {
$newm = 9;
}else{
$newm = $m;
}
// Check if day is registered in db
$query = mysqli_query($link, "SELECT * FROM lime_survey_669629 WHERE
token = '$token' AND 669629X3X15 = '$newDate'") or die(mysqli_error());
// start array bracket
echo '[';
// define count variable
$c = mysqli_num_rows($query);
// check count
if($c == 0) {
// if count is 0, register day with value 0
$output = '['.$y.'-'.$newm.'-'.$d.',0],';
echo $output;
}else{
// if count is more than 0, output datasets
while($row = mysqli_fetch_array($query)) {
$oldValue = $row['669629X5X275'];
$modValue = explode("=", $oldValue);
$value = $modValue['2'];
// output dfatasets in a json array
$output = '['.$y.'-'.$newm.'-'.$d.','.$value.'],';
echo $output;
}
}
// end array bracket
echo ']';
}
}
「* ..調用一個Ajax請求。但是,當我運行該腳本,我得到一個錯誤500內部服務器錯誤。*」。那麼,那個** Ajax Script **在哪裏? –
檢查你的AJAX請求的響應,並查看你的錯誤日誌,看看發生了什麼。 –
500表示服務器出現錯誤。檢查您的PHP日誌和Web服務器日誌,打開PHP錯誤報告等。*找到錯誤消息*,而不是隻看代碼並試圖猜測。 – David