SQL查詢獲取真實日期和日期時間差異

Question

我需要獲取已經開始但尚未完成的旅程。到目前爲止，我有這個。

//DepartureDate and Returndate are Datetime Types 

    $sql = "SELECT * FROM Orders WHERE departureDate <= GETDATE() >= returndate"; 

Answer 1

$sql = "SELECT * FROM Orders WHERE departureDate > GETDATE() AND returndate <= GETDATE()"; 

Answer 2

假設你正在使用SQL Server，剛剛突破的邏輯分爲兩個部分：

SELECT o.* 
FROM Orders o 
WHERE o.departureDate <= GETDATE() AND 
     GETDATE() >= o.returndate