我想使用單個腳本在不同的時間啓動多個進程。然而,我沒有想到,當我嘗試使用它開始第二個過程時它已經在運行。所以我正在尋找能夠幫助我實現這一目標的東西。使用單個啓動腳本啓動多個進程並保持運行
任何幫助是非常讚賞,並且如果需要任何更多的信息,請讓我知道....
前。什麼,我想(與後來的運行它再次)做
./startup.sh QWER start
./startup.sh ASDF start
基本腳本接受兩個參數,將只檢查,以確保隊列管理器存在,然後使用case語句停止/啓動/檢查以下狀態等
腳本...
#!/bin/bash
#### Define vars #########################
qm=$1
QM=${qm^^}
stat=$2
proc=[I]ntroscopeAgent_$QM
MQMONITOR_BINDIR=/opt/bin/MQMonitor_$QM
#### Define New QUEUE MANAGERS ###########
declare -a QMGR=('QWER' 'ASDF' 'ZXCV' 'ASDF');
##########################################
if [[ " ${QMGR[@]} " =~ " $QM " ]]; then
case "$stat" in
start)
C=`ps -eo pid,args | grep "MQMonitor" | grep -c $proc`
if [ ${C} -gt 0 ]; then
proc_dtl=`ps -eo pid,args | grep "MQMonitor" | grep $proc`
echo -e "\n\033[7mMQMonitor is running:\033[0m ${proc_dtl}\n\n\033[1mEither stop or restart the process\n\033[0m"
exit 1
fi
echo -e "\nStarting MQMonitor MQ 9 "
${MQMONITOR_BINDIR}/startMQMonitor.sh &
if [ $? -eq 0 ]; then
echo -e "\033[0mMQMonitor Started.. (Please see start up log in \033[1m$logfile \033[0m) \n\033[0m"
else
echo -e "\033[01;31mMQMonitor ${MQMONITOR_BINDIR}/startMonitor.sh didn't start cleanly\n\033[0m"
fi
;;
stop)
echo -e "\nStopping MQMonitor ..."
${MQMONITOR_BINDIR}/stopMQMonitor.sh
if [ $? -eq 0 ]; then
echo -e "\033[01;31mMQMonitor stopped\n\033[0m"
else
echo -e "\033[01;31mCouldn't stop MQMonitor\n\033[0m"
fi
;;
status)
C=`ps -eo pid,args | grep "MQMonitor" | grep -c $proc`
if [ ${C} -gt 0 ]; then
PROC_ID=`ps -eo pid,args | grep "MQMonitor" | grep $proc | awk '{print $1}'`
echo -e "\n\033[1m\033#6MQMonitor running PID: ${PROC_ID}\n\033[0m"
else
echo -e "\nMQMonitor not running\n"
fi
;;
restart|reload)
C=`ps -eo pid,args | grep "MQMonitor" | grep -c $proc`
if [ ${C} -gt 0 ]; then
echo "MQMonitor Running..."
echo "Stopping MQMonitor"
${MQMONITOR_BINDIR}/stopMQMonitor.sh
if [ $? -eq 0 ]; then
echo "MQMonitor stopped"
else
echo "Couldn't stop MQMonitor"
exit 1
fi
echo "Stopped"
echo "Starting MQMonitor"
${MQMONITOR_BINDIR}/startMQMonitor.sh &
if [ $? -eq 0 ]; then
echo "MQMonitor Started"
else
echo "MQMonitor ${MQMONITOR_BINDIR}/startMonitor.sh didn't start cleanly"
fi
else
echo "MQMonitor not running"
echo "Starting MQMonitor"
${MQMONITOR_BINDIR}/startMQMonitor.sh &
if [ $? -eq 0 ]; then
echo "MQMonitor Started"
else
echo "MQMonitor ${MQMONITOR_BINDIR}/startMonitor.sh didn't start cleanly"
fi
fi
;;
*)
echo -e $"\n\n\e[41mSYNTAX ERROR:\033[0m\tPlease Use Proper Syntax: QMGR {start|stop|status|restart}\n\e[41mEx:\033[0m\t\t./mqagent QPX1 status\n\n"
exit 1
esac
else
echo -e "\n\n\e[41mPlease enter a valid Queue Manager\033[0m\n\n"
fi
因此,當我第二次運行該腳本時,它似乎在第一次運行時使用傳遞給它的相同參數。我不知道如何解決這個問題。 –