如何在PHP中合併兩個類？

Question

使最終類有兩個類

所有成員變量/方法有沒有一種簡單的方法去嗎？

Answer 1

您應該封裝中含有類兩個類別，並提供了相應的接口（如私有變量

class YourFirstClass { 
    public $variable; 
    private $_variable2; 
    public function setVariable2($a) { 
     $this->_variable2 = $a; 
    } 
} 

class YourSecondClass { 
    public $variable; 
    private $_variable2; 
    public function setVariable2($a) { 
     $this->_variable2 = $a; 
    } 
} 

class ContaingClass { 
    private $_first; 
    private $_second; 
    public function __construct(YourFirstClass $first, YourSecondClass $second) { 
     $this->_first = $first; 
     $this->_second = $second; 
    } 
    public function doSomething($aa) { 
     $this->_first->setVariable2($aa); 
    } 
} 

研究（谷歌）制定者/吸氣：「組成了繼承」

腳註：對於非創造性的變量名稱感到抱歉。

Answer 2

您是要求在運行時或編程時執行此操作嗎？
我將假定運行時，在這種情況下使用c1有什麼問題屁股inheritance？
創建一個從您想要合併的兩個繼承的新類。

Answer 3

# Merge only properties that are shared between the two classes into this object. 
public function conservativeMerge($objectToMerge) 
{ 
    # Makes sure the argument is an object. 
    if(!is_object($objectToMerge)) 
     return FALSE; 

    # Used $this to make sure that only known properties in this class are shared. 
    # Note: You can only iterate over an object as of 5.3.0 or greater. 
    foreach ($this as $property => $value) 
    { 
     # Makes sure that the mering object has this property. 
     if (isset($objectToMerge->$property)) 
     { 
      $objectToMerge->$property = $value; 
     } 
    } 
} 


# Merge all $objectToMerge's properties to this object. 
public function liberalMerge($objectToMerge) 
{ 
    # Makes sure the argument is an object. 
    if(!is_object($objectToMerge)) 
     return FALSE; 

    # Note: You can only iterate over an object as of 5.3.0 or greater. 
    foreach ($objectToMerge as $property => $value) 
    { 
     $objectToMerge->$property = $value; 
    } 
} 

你首先應該考慮的方法，就好像它在那裏的array_combine()的對象對應。然後考慮第二種方法，就好像它在array_merge()的對象所在的位置。