我正在尋找一種Python技術,以從熊貓數據框架中的平坦表格構建嵌套的JSON文件。例如怎麼可能是大熊貓的數據幀表,例如:如何使用平面數據表構建嵌套記錄的JSON文件?
teamname member firstname lastname orgname phone mobile
0 1 0 John Doe Anon 916-555-1234
1 1 1 Jane Doe Anon 916-555-4321 916-555-7890
2 2 0 Mickey Moose Moosers 916-555-0000 916-555-1111
3 2 1 Minny Moose Moosers 916-555-2222
採取並出口到一個JSON看起來像:通過創建類型的字典字典和傾倒
{
"teams": [
{
"teamname": "1",
"members": [
{
"firstname": "John",
"lastname": "Doe",
"orgname": "Anon",
"phone": "916-555-1234",
"mobile": "",
},
{
"firstname": "Jane",
"lastname": "Doe",
"orgname": "Anon",
"phone": "916-555-4321",
"mobile": "916-555-7890",
}
]
},
{
"teamname": "2",
"members": [
{
"firstname": "Mickey",
"lastname": "Moose",
"orgname": "Moosers",
"phone": "916-555-0000",
"mobile": "916-555-1111",
},
{
"firstname": "Minny",
"lastname": "Moose",
"orgname": "Moosers",
"phone": "916-555-2222",
"mobile": "",
}
]
}
]
}
我曾嘗試這樣做到JSON。這是我當前的代碼:
data = pandas.read_excel(inputExcel, sheetname = 'SCAT Teams', encoding = 'utf8')
memberDictTuple = []
for index, row in data.iterrows():
dataRow = row
rowDict = dict(zip(columnList[2:], dataRow[2:]))
teamRowDict = {columnList[0]:int(dataRow[0])}
memberId = tuple(row[1:2])
memberId = memberId[0]
teamName = tuple(row[0:1])
teamName = teamName[0]
memberDict1 = {int(memberId):rowDict}
memberDict2 = {int(teamName):memberDict1}
memberDictTuple.append(memberDict2)
memberDictTuple = tuple(memberDictTuple)
formattedJson = json.dumps(memberDictTuple, indent = 4, sort_keys = True)
print formattedJson
這產生了以下輸出。每個項目嵌套在「teamname」1或2下的正確級別,但如果記錄具有相同的組名,則記錄應嵌套在一起。我該如何解決這個問題,以便teamname 1和teamname 2每個嵌套2條記錄?
[
{
"1": {
"0": {
"email": "[email protected]",
"firstname": "John",
"lastname": "Doe",
"mobile": "none",
"orgname": "Anon",
"phone": "916-555-1234"
}
}
},
{
"1": {
"1": {
"email": "[email protected]",
"firstname": "Jane",
"lastname": "Doe",
"mobile": "916-555-7890",
"orgname": "Anon",
"phone": "916-555-4321"
}
}
},
{
"2": {
"0": {
"email": "[email protected]",
"firstname": "Mickey",
"lastname": "Moose",
"mobile": "916-555-1111",
"orgname": "Moosers",
"phone": "916-555-0000"
}
}
},
{
"2": {
"1": {
"email": "[email protected]",
"firstname": "Minny",
"lastname": "Moose",
"mobile": "none",
"orgname": "Moosers",
"phone": "916-555-2222"
}
}
}
]
不幸的是,關於問題的高層次方法是好/正確/可能/等等的不幸的問題不在這裏討論。這就是說,我認爲口述的方法*看起來很有希望。你應該使用你的其他問題來解決其餘的細節問題,但記住要更新你收到的錯誤信息*以及你正在使用的代碼,以便它們同步(否則你的問題是不可複製的) 。 –
我也試着調整這個答案:http://stackoverflow.com/questions/24374062/pandas-groupby-to-nested-json,但仍然沒有骰子。 – spaine